International Institute of Information Technology, Pune All Questions

Hello there,
According to the formula, [100-75*869010/100], your All India Rank is 217252. Since you belong to the OBC category, your category rank will be around 88000 approximately. You haven't mentioned which branch you want to choose.

The cut-off ranks for different branches in IIIT Pune are as follows:
CSE- 9799
ECE- 12453
You can check the cut-off rank for all the categories in the link given below:
https://www.google.com/amp/s/engineering.careers360.com/articles/jee-main-cutoff-for-iiit-pune/amp

Also note that the cut-off rank changes every year depending on the difficulty of the paper,and the number of candidates appearing for it. I would suggest you to appear for the second phase of JEE Main and try to score better percentile.

You can use our college predictor:
https://engineering.careers360.com/college-predictor

Hope this answer helps you.
Good luck!!

IIIT Pune doesn't offer admission on the basis of MHT CET score. Admissions into the B.Tech programme in IIIT Pune is based on the score obtained in JEE Main and followed by JOSAA counselling. Admission is only based on All India Rank. State rank is not considered for admission to IIITs.

Hello!!

Hope you are doing great!!!

Your All India Rank would be around 60917 approximately,Calculated by using the formula 100-92.99*869010/100 where 92.99 is your mains percentile and 869010 is the number of candidates appeared in January session.As per the previous year cutoff trends,With this rank you can not get seat in IIT Pune.The previous year cutoss for Computer Science for OBC Category is around 9799 AIR.You may have to appear for july session.You can check the previous year cutoff for IIIT Pune in the link provided below:

https://www.careers360.com/university/indian-institute-of-information-technology-pune/cut-off?

For checking the probabilities of colleges,you can use our college predictor: https://engineering.careers360.com/jee-main-college-predictor

Hope it helps you!!!

Hello,

Your expected rank will be around 60917 and the formula to calculate it is (100-your total percentile)*869010/100

In January session 869010 candidates appeared in JEE Main. Your rank based on category will be in between 16000-18000. It is not mentioned if you belong to OBC-NCL or OBC-CL, if you belong to OBC-CL then you will come under general category.In 2019 the cut off in round 7 for IIIT, Pune for CSE was 9799. This is for OBC-NCL category and for general category it was 23660. Considering this you may get seat whether you belong to OBC-NCL or OBC-CL. However, cut off changes depending on number of candidates appeared, difficulty of exam, number of seats available etc.

You may try our JEE main college predictor to know the colleges you may get https://engineering.careers360.com/jee-main-college-predictor

Hey Mohan

With rank formula ((100-Your percentile)*869010/100), your General rank with 92.99 percentile comes out to be around AIR 61,000. Last year cutoff was:

• IIIT Pune, OBC candidate: 9799 rank for CSE

Analysing your rank to OBC category, sorry but it would be difficult for you to take admission in CSE at IIIT Pune. You may give your best in July attempt and increase your score.

Note: This data is on the basis of previous year record and may change in the upcoming sessions depending upon cutoff and number of candidates appearing. For further doubts, visit; IIIT Pune

Hello student you can calculate and get your rank easily by using this formula

100 -( your total percentile) 869010 /100

In your case your rank must be around - 43,450

Cut off vary every year on various factors like the level of question in the entrance examination and total number of applicants in that examination.

As per previous year records its expected that you need to secure rank around 5000 (EWS) I hello student

Last year the cut off for EWS category was 4591

For more updates refer to the link mentioned below - https://www.google.com/amp/s/engineering.careers360.com/articles/jee-main-cutoff-for-iiit-pune/amp

Feel free to comment if you have any doubt

Good luck

Hello student cut off vary every year on various factors like the level of question in the entrance examination and total number of applicants in that examination. As per previous year records its expected that you need to secure rank under 5,000(Genral AIQ) to get admission into iiit pune.

You can also subscribe to careers360 knockout package for preparing and qualifying the entrance examination, it offer you 100 percent money back guarantee if you do not qualify - https://learn.careers360.com/knockout-jee-main-april/

Feel free to comment if you have any doubt

Good luck

Hi Vaishnavi

IIIT Pune is undoubtedly better for B.Tech in Computer Science. Although relatively newer, it is a budding institute and mentored by the older IIITs. The faculty members are well experienced, placement stats high and the infrastructure is quite good. The kind of exposure you will get here is comparable to other top IIITs.

For more information on IIIT Pune refer the following link:

https://www.careers360.com/university/indian-institute-of-information-technology-pune

Hi,

You can always use the careers360 college compare to find out which college is best to pursue your dream course. You will get to know all the details about the college including the NAAC score, Placement details, college facilities and also you can find out reviews of the college written by the students who study in that particular college.

I have provided the link below. Use this link to find out which college is best. https://www.careers360.com/compare-colleges

I hope it helps.

hello mohan

well this year's cutoff hasnt been released yet so you can compare to last years cutoff for iiit pune and  estimate whether you can get a seat in the branch of cse

Course Name	Category	Gender Neutral	Female
Computer Science and Engineering	OBC	9799	--
	EWS	3613	--
	General	23600	--
	SC	5791	--
	ST	2810	--