NIT Kurukshetra All Questions

Hello Aspirant,

I'm providing the link through which you can get the previous years cut off's for NIT Kurukshetra. Since you haven't mention whether you're looking for JEE Main cut off or GATE cut off, I'll provide the link for both.

https://www.google.com/amp/s/engineering.careers360.com/articles/jee-main-cutoff-for-nit-kurukshetra/amp

https://engineering.careers360.com/articles/gate-cutoff-for-nit-kurukshetra/amp

Hello!!!!!

Hope you are doing great!!!

Kartik,Your All India rank would be 3,38,913 approximately by using the formula 100-61*869010/100 where 61 is your percentile and 869010 is the number of students who appeared in the january session.As per the previous year scenario,With this rank you can not get seat in Computer science ,electrical and electronics engineering under home state quota and your category.You may have to appear for the July session.For checking the probabilities of colleges or NIT's , you can use our college predictor.The link is mentioned below:

https://engineering.careers360.com/jee-main-college-predictor?ici=cp-listing_engineering&icn=JEE-Main-College-Predictor Hope it helps!!!

All the best!!!!!

Hello student National institute of technology,Kurukshetra has total 9 boys hostel 3 hostel are triple bedded and rest of them are single bedded all the hostel of Postgraduate students are single bedded. You need to contact the administration department to get the accommodation and on the basis of availability they'll alot you on respective hostel.

For more updates refer to the link mentioned below - https://nitkkr.ac.in/sub_courses.php?id=268

Feel free to comment if you have any doubt

Good luck

Hi there,

If you get a chance to chose between these two college then go for jadavpur university without any second thought.

As jadavpur is one the best college in the  nation and far better than any nit on the basis of education placement fees etc.

I hope this help

Going by the formula 100-98.48*869010/100 wherein 98.48 is your percentile and 869010 is the no.of Candidates who appeared for January session, your All India Rank is 13208. Now we do not have Category based ranks yet. And in 2019, the cut offs for Home State EWS Female Candidate for various streams have been as follows:

Civil: 5869

Electrical: 4311

ECE: 3419

Mechanical: 5347

Production and Industrial Engineering: 6731

IT: 2227

CSE: 1266

Now this is 2019 data and cut offs change every year. You might have decent chances in NIT Calicut, NIT Uttarakhand, NIT AP, NIT Puducherry, among others. Please use our College predictor for the complete list of colleges that you might have a shot at: https://engineering.careers360.com/jee-main-college-predictor

Considering rank formula, your rank will be arounf 45k to 46k. So Aniket, with this rank  it is pretty tough to get CSE in any NIT's. If you consider last year cutoffs or percentile then students with 96.5 too were not able to get CSE. You can get IT in North Eastern NIT's or even Kurukshetra. Just work hard hard for Advance.

Hi there,

Since your percentile is also good and you belong to obc category plus you have home state quota as well. So u have high chances of getting into nit kurukshetra. Not sure about core branch.

I hope this help

Hello Aspirant,

As we know that results of JEE-Main January session are declared in percentile form so exact rank cannot be predicted from percentile. Here we have a formula through which we can predict the near about rank, formula is

(100 - your percentile) *869010/100

According to this formula your rank would be around 2 Lakhs. So on this rank it is not possible to get seat in NIT Kurukshetra whether you belong to any reservation category or not.

I would suggest you to prepare yourself for April session of JEE-Main 2020 . You can use the preparation tips for JEE-Main for better preparation.

You can use JEE-Main College Predictor to predict the best college according to your percentile and category.

I hope your question has been answered properly.

All the best!!