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Question : Bacterial and fungal enzymes degrade detritus into simpler inorganic substances. This process is called ______.
Option 1: catabolism
Option 2: fragmentation
Option 3: leaching
Option 4: decomposition
Correct Answer: catabolism
Solution : The correct option is catabolism
The process of breaking down complex organic molecules into simpler ones, often associated with the release of energy, is called "catabolism." Decomposition is a specific form of catabolism, where organic matter, such as detritus, is broken down by microorganisms into
Question : Directions: Select the Venn diagram that best illustrates the relationship between the following classes. Humans, Professionals, Girls
Option 1:
Option 2:
Option 3:
Option 4:
Correct Answer:
Solution : Based on the general information, both girls and professionals are humans. So, two circles representing girls and professionals will lie inside the circle that represents humans. Also, some girls can be professionals and some professionals can also be girls. So, their circles will overlap each other
Question : Given that $\sqrt3=1.732$, the value of $\frac{3+\sqrt6}{5\sqrt3-2\sqrt{12}-\sqrt{32}+\sqrt{50}}$ is:
Option 1: 4.899
Option 2: 2.551
Option 3: 1.414
Option 4: 1.732
Correct Answer: 1.732
Solution : Given: $\sqrt{3}=1.732$ $\frac{3+\sqrt{6}}{5\sqrt{3}-2\sqrt{12}-\sqrt{32}+\sqrt{50}}$ Now evaluate: $= \frac{3+\sqrt{6}}{5\sqrt{3}-2\sqrt{4\times3}-\sqrt{16\times2}+\sqrt{25\times2}}$ $=\frac{3+\sqrt{6}}{5\sqrt{3}-4\sqrt{3}-4\sqrt{2}+5\sqrt{2}}$ $=\frac{3+\sqrt{6}}{5(\sqrt{3}+\sqrt{2})-4(\sqrt{3}+\sqrt{2})}$ $=\frac{3+\sqrt{6}}{\sqrt{3}+\sqrt{2}}$ Now multiply and divide with $\sqrt{3}-\sqrt{2}.$ $=\frac{3+\sqrt{6}}{\sqrt{3}+\sqrt{2}}\times\frac{\sqrt{3}-\sqrt{2}}{\sqrt{3}-\sqrt{2}}$ $=\frac{3\sqrt{3}-3\sqrt{2}+\sqrt{18}-\sqrt{12}}{3-2}$ $=\frac{3\sqrt{3}-3\sqrt{2}+\sqrt{9\times2}-\sqrt{4\times3}}{1}$ $=3\sqrt{3}-3\sqrt{2}+3\sqrt{2}-2\sqrt{3}$ $=3\sqrt{3}-2\sqrt{3}$ $=\sqrt{3}(3-2)$ $=\sqrt{3}$ $=1.732$ Hence, the correct answer is 1.732.
Question : The value of $\left(\operatorname{cosec}^2 B-1\right)\left(\sec ^2 B-1\right)$ is:
Option 1: 4
Option 2: 3
Option 3: 2
Option 4: 1
Correct Answer: 1
Solution : Given: $\left(\operatorname{cosec}^2 B-1\right)\left(\sec ^2 B-1\right)$ We know that $\operatorname{cosec}^2 B = 1 + \cot^2 B$ $\sec^2 B = 1 + \tan^2 B$ $\left(\operatorname{cosec}^2 B-1\right)\left(\sec ^2 B-1\right) = \cot^2 B\times\tan^2 B$. $=\cot^2 B \times \tan^2 B = \frac{1}{\tan^2 B}\times\tan^2 B = 1$ Hence, the correct answer
Question : At Barren Island ,the only active volcano in India is situated in
Option 1: Andaman Island
Option 2: Nicobar Island
Option 3: Lakshdweep
Option 4: Minicoy
Correct Answer: Andaman Island
Solution : The correct answer is Andaman Island.
Andaman and Nicobar islands are of volcanic origin. Barren Island is the only active stratovolcano in India. It is located in Andaman Island. Recently it has erupted in May 2023. It also had small eruptions in 2017 and
Question : Directions: Select the combination of letters that when sequentially placed in the blanks of the given series will complete the series. a b _ a _ b b a _ _ b a
Option 1: abbb
Option 2: aaaa
Option 3: bbbb
Option 4: baab
Correct Answer: baab
Solution : Given: a b _ a _ b b a _ _ b a
To fill the series we have to divide the series – a b _ a \ _ b b a \ _ _ b a
Let's check each option – First option:
Question : Select the most appropriate antonym to substitute the bracketed word in the given sentence.
She ventured to go back to the tree of the (tryst), the mulberry with the shining white fruit.
Option 1: Rendezvous
Option 2: Engagement
Option 3: Date
Option 4: Separation
Correct Answer: Separation
Solution : The correct option will be the fourth option.
The word "tryst" typically refers to a secret meeting or rendezvous, often associated with lovers. In the context of the sentence, the person is going back to the tree where a significant or secretive meeting
Question : What is the approximate height (in metres) of the Qutub Minar situated in Delhi?
Option 1: 75
Option 2: 77
Option 3: 73
Option 4: 71
Correct Answer: 73
Solution : The correct option is 73.
The Qutub Minar, located in Delhi, India, is approximately 73 metres (240 feet) tall. The construction of the Qutub Minar was initiated by Qutb-ud-din Aibak, the founder of the Delhi Sultanate, in 1192. It was later completed by his
Question : If $p-\frac{1}{p}=6$, then what is the value of $p^4+\frac{1}{p^4}$?
Option 1: 1562
Option 2: 1432
Option 3: 1442
Option 4: 1444
Correct Answer: 1442
Solution : $\mathrm{p}-\frac{1}{\mathrm{p}}=6$ Squaring both sides, we get, $⇒p^2+\frac{1}{p^2}-2(p)(\frac{1}{p})=36$ $⇒p^2+\frac{1}{p^2}-2=36$ $⇒p^2+\frac{1}{p^2}=38$ Squaring both sides again, we get, $⇒p^4+\frac{1}{p^4}+2(p^2)(\frac{1}{p^2})=1444$ $⇒p^4+\frac{1}{p^4}+2=1444$ $\therefore p^4+\frac{1}{p^4}=1442$ Hence, the correct answer is 1442.
Question : The compound interest received on INR 18,000 for 2 years is INR 7,920 when the interest is compounded annually. What is the rate of interest per annum?
Option 1: 15%
Option 2: 12.5%
Option 3: 20%
Option 4: 25%
Correct Answer: 20%
Solution : Given: Compound interest = INR 7920 Principal = INR 18,000 Time = 2 years Compound interest $= \text{Principal}×((1+\frac{\text{Rate}}{100})^{\text{Time}}-1)$ ⇒ $7920=18000×((1+\frac{\text{Rate}}{100})^{2}-1)$ ⇒ $\frac{7920}{18000}=((1+\frac{\text{Rate}}{100})^{2}-1)$ ⇒ $\frac{11}{25}+1=(1+\frac{\text{Rate}}{100})^{2}$ ⇒ $\frac{36}{25}=(1+\frac{\text{Rate}}{100})^{2}$ ⇒ $\frac{6}{5}=1+\frac{\text{Rate}}{100}$ ⇒ $\frac{6}{5}-1=\frac{\text{Rate}}{100}$ ⇒ $\frac{1}{5}=\frac{\text{Rate}}{100}$ $\therefore$ Rate $= 20$% Hence, the correct answer is 20%.
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