Question : If $2x+3y=16$ and $xy=9$, then find the value of $8x^3+27y^3$.
Option 1: 1980
Option 2: 2980
Option 3: 1504
Option 4: 2189
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Correct Answer: 1504
Solution :
Given: $2x+3y=16$ and $xy=9$
We know that $(a+b)^{3}=a^{3}+b^{3}+3ab(a+b)$
⇒ $(2x+3y)^{3}=8x^{3}+27y^{3}+18xy(2x+3y)$
Putting the given values, we have,
⇒ $(16)^{3}=8x^{3}+27y^{3}+18×9×(16)$
⇒ $4096=8x^{3}+27y^{3}+2592$
⇒ $8x^{3}+27y^{3}=4096–2592$
⇒ $8x^{3}+27y^{3}=1504$
Hence, the correct answer is 1504.
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