Question : In a triangle, ABC, P, and Q are points on AB and AC, respectively, such that AP = 1 cm, PB = 3 cm, AQ = 1.5 cm, and CQ = 4.5 cm. If the area of $\triangle \mathrm{APQ}$ is 12 cm2, then find the area of BPQC.
Option 1: 192 cm2
Option 2: 182 cm2
Option 3: 190 cm2
Option 4: 180 cm2
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Correct Answer: 180 cm 2
Solution :
Given: AP = 1 cm, PB = 3 cm, AQ = 1.5 cm, and CQ = 4.5 cm
AB = AP + PB = 1 + 3 = 4
AC = AQ + CQ = 1.5 + 4.5 = 6 cm
In $\triangle ABC$ and $\triangle APQ$
$\angle A = \angle A$ (Common angle)
⇒$ \frac{AP}{AB}=\frac{1}{4}$, and $\frac{AQ}{AC}=\frac{1.5}{6}=\frac{1}{4}$
Thus, $\triangle APQ$ and $\triangle ABC$ are similar
Using the formula,
$\frac{\text{Area of triangle APQ}}{\text{Area of triangle ABC}}=(\frac{AP}{AB})^2$
⇒ $\frac{\triangle APQ}{\triangle ABC} = (\frac{1}{4})^2 = \frac{1}{16}$
⇒ $\frac{12}{\triangle ABC} = \frac{1}{16}$
⇒ $\triangle ABC = 192$ cm
2
Thus, Area of BPCQ = $\triangle ABC - \triangle APQ$
= 192 – 12 = 180
Area of BPCQ = 180 cm
2
Hence, the correct answer is 180 cm
2
.
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