Question : The minimum value of $4\tan^{2}\theta+9\cot^{2}\theta$ is equal to:
Option 1: 0
Option 2: 5
Option 3: 12
Option 4: 13
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Correct Answer: 12
Solution :
Given: $4\tan^{2}\theta+9\cot^{2}\theta$
The minimum value of $a\tan^{2}\theta+b\cot^{2}\theta=2\sqrt{ab}$
Comparing with the above expression, we get:
$a=4$ and $b=9$
The minimum value of $4\tan^{2}\theta+9\cot^{2}\theta=2\sqrt{9×4}=12$
Hence, the correct answer is 12.
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