Question : The radius of a hollow sphere is 21 cm. It is cut into two equal halves by a plane passing through its centre. What is 75% of the curved surface area (in cm2, rounded off to the nearest tens) of the hemisphere? (Take $\pi=\frac{22}{7}$ )
Option 1: 4160
Option 2: 3470
Option 3: 2080
Option 4: 2770
Correct Answer: 2080
Solution :
Here, radius, $r$ = 21 cm
The curved surface area of a hemisphere $= 2\pi r^2=2×\frac{22}{7}×21^2=2772\ \text{cm}^2$
75% of the curved surface area $= 2772×\frac{75}{100}=2079\ \text{cm}^2$
If we round off it to the nearest tens, we get 2080 cm
2
.
Hence, the correct answer is 2080 cm
2
.
Related Questions
Know More about
Staff Selection Commission Sub Inspector ...
Application | Eligibility | Selection Process | Result | Cutoff | Admit Card | Preparation Tips
Get Updates BrochureYour Staff Selection Commission Sub Inspector Exam brochure has been successfully mailed to your registered email id “”.




