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Hello..
For your percentile the approximate predicted rank will be around 7,145.
The predicted rank formula is (100-percentile)*145386/100.
For this rank you have very less chances of getting the seat if we compare with the previous years closing ranks.
For more details please visit the link:
https://www.careers360.com/university/school-of-planning-and-architecture-vijayawada/cut-off
All the best..
Thank you for consulting careers360

Hello 

Your expected rank is about 63,960. The chances of getting into SPA or NIT is quite slim. You can expect a category rank less than 10000, however, you might not get a seat with this rank too. It's best that you try to improve your performance in the April session of the exam.

Good luck!

Hello aspirant

As per your percentile I.e., 97.48 in JEE paper 2 u can easily get in NITs.The minimum aggregate score I.e.,for general category should be above 75%.

So there is chance for you to get NITs.

Hope this information is relevant to your question.

If you have any enquiries please feel free to ask.

Thank you:)

Congratulations for getting good marks. As per your marks your predicted rank would be 2411. So with this rank you will surely get a IIT for B.Arch.


NCU is famous as one of the best Engineering universities with best placements. School of Professional Attachment (SPA) has been established at NCU to build and enrich your potential and help you plan your career better. SPA will nurture you from the time you join the University till you finally get a good placement - it acts as a bridge between you and your first job. For your holistic development, ready to face contemporary challenges of the corporate world and for your smooth transition from the campus to the corporate world, SPA will equip you with the right kind of skills and attitude so that you can become more effective, efficient and productive in your employer’s organization. We help students with best Engineering Placements.

Hello Arindam,

Firstly congratulations on your good result. Yes you might have a chance to get in as you belong to the reserve category and your score is quite good. So there is a chance of getting in SPA, Delhi but final result will depend upon on your final merit list and the rank which you'll get in April. I'm giving you a link with previous years cutoff of all relevant Colleges along with category rank. Do have a look and plan accordingly https://www.google.com/amp/s/engineering.careers360.com/articles/jee-main-cutoff-for-b-arch-b-planning/amp .

All the best for your career. Feel free to ask.

As you will become local here so you belong to obc category so you have to score a percentile of about 89 percentile so that you can get in local category too and once category too as it was a very good college so you can definitely join in that college undoubtedly , so all the best for your future 

HELLO MADHAV!

First of all congrats for scoring such awesome percentile.I can give you rough idea about your rank under general quota using this formula:Probable ranl=(100-percentile score)*145386/100,where 145386 is total number of candidates that appeared in 1st phase of jee mains of paper2.Your rank will be around 2.6k under general category.To get NITs you need rank under 2k.For BIT mersa closing rank is 3.8k under HS quota and 1.8k under OS quota.For surety wait till arpil.NTA will release rank after compilation of both phases result.You still have one attempt for jee mains paper2.

Let me know if you have any other queries.

GOOD LUCK!

The exact prediction would be tough as JEE Main is being conducted twice by NTA for the first time and rank will be based on NTA percentile. As a total No. of 1,45,386 candidates had appeared for January Session, Using the Formula (100-your score)* 1,45,386 / 100- Your Expected rank will be 7,385. As per the previous year cutoff trends with this rank the chances seems less to get a seat in NIT Tiruchirappalli & SPA Delhi.

You can also check the previous year cutoff with the given below link.

https://engineering.careers360.com/articles/jee-main-cutoff-for-b-arch-b-planning


NOTE: This is only a prediction. NTA will merge the scores obtained in first and second attempt by candidates of JEE Main Paper 2 2019 for the compilation and preparation of overall merit/rank list. The rank will be released on 30th April, 2019.

 

 

Good Luck!

 

As a total No. of 1,45,386 candidates had appeared for January Session, Using the Formula (100-your score)* 1,45,386 / 100- Your Expected rank will be 7,385. NITs cutoff varies to Home state quota & Other state quota, With this rank the chances seems less to get a seat in NITs & SPA Delhi, The exact prediction would be tough as JEE Main is being conducted twice by NTA for the first time and rank will be based on NTA percentile.

You can also check the previous year cutoff with the given below link.

https://engineering.careers360.com/articles/jee-main-cutoff-for-b-arch-b-planning

 

 

NOTE: This is only a prediction. NTA will merge the scores obtained in first and second attempt by candidates of JEE Main Paper 2 2019 for the compilation and preparation of overall merit/rank list. The rank will be released on 30th April, 2019.

 

 

Good Luck!

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