SPA Delhi All Questions

The exact prediction would be tough as JEE Main is being conducted twice by NTA for the first time and rank will be based on NTA percentile. As a total No. of 1,45,386 candidates had appeared for January Session, Using the Formula (100-your score)* 1,45,386 / 100- Your Expected rank will be 7,385. As per the previous year cutoff trends with this rank the chances seems less to get a seat in NIT Tiruchirappalli & SPA Delhi.

You can also check the previous year cutoff with the given below link.

https://engineering.careers360.com/articles/jee-main-cutoff-for-b-arch-b-planning

NOTE: This is only a prediction. NTA will merge the scores obtained in first and second attempt by candidates of JEE Main Paper 2 2019 for the compilation and preparation of overall merit/rank list. The rank will be released on 30th April, 2019.

Good Luck!

As a total No. of 1,45,386 candidates had appeared for January Session, Using the Formula (100-your score)* 1,45,386 / 100- Your Expected rank will be 7,385. NITs cutoff varies to Home state quota & Other state quota, With this rank the chances seems less to get a seat in NITs & SPA Delhi, The exact prediction would be tough as JEE Main is being conducted twice by NTA for the first time and rank will be based on NTA percentile.

You can also check the previous year cutoff with the given below link.

https://engineering.careers360.com/articles/jee-main-cutoff-for-b-arch-b-planning

NOTE: This is only a prediction. NTA will merge the scores obtained in first and second attempt by candidates of JEE Main Paper 2 2019 for the compilation and preparation of overall merit/rank list. The rank will be released on 30th April, 2019.

Good Luck!

As per your percentile your predicted rank will be 32k. you will get colleges as Kohlapur institute of technology, New horizon institute of technology, Thane.

If you apply through state quota there will be chace that you will get DTU.

Hello krish

Well, it's very difficult as of now,to predict the cutoff for JEE mains paper 2 based on percentile.You can first calculate your rank by rank=(100-percentile)*145386/100.With this rank,you can compare previous year's cutoff for different colleges and can predict some of the colleges you may be getting.But remember this is not the final rank.It will change based on the april session of mains.For more colleges visit https://engineering.careers360.com/jee-main-rank-predictor  .Hope this helps.

Good Luck!

Hello janardhan,

On the basis of the rank only the cutoff for college is decided. U can expect it to vary after the NTA releases the final result post the April session.We can't predict the college.You can go for college predictor which Colleges are available for your percentile.

You can predict the college by your percentile from the link given below from careers 360 -

https://engineering.careers360.com/jee-main-architecture-college-predictor

You can use the above link by copying and pasting it in the url bar of your browser.

All the best!

Thanku.

Dear aspirant, 

Your rank will be nearly (100-95.6)*145386/100=6396 based on previous year trends.And chances are there with NITs

You have chances with

NIT raipur

NIT Hamirpur

For last year NIT cutoffs go to

https://www.google.com/amp/s/engineering.careers360.com/articles/jee-main-cutoff-for-b-arch-b-planning/amp

Good luck