SPA Delhi All Questions

As you will become local here so you belong to obc category so you have to score a percentile of about 89 percentile so that you can get in local category too and once category too as it was a very good college so you can definitely join in that

HELLO MADHAV!

First of all congrats for scoring such awesome percentile.I can give you rough idea about your rank under general quota using this formula:Probable ranl=(100-percentile score)*145386/100,where 145386 is total number of candidates that appeared in 1st phase of jee mains of paper2.Your rank will be around 2.6k under general

The exact prediction would be tough as JEE Main is being conducted twice by NTA for the first time and rank will be based on NTA percentile. As a total No. of 1,45,386 candidates had appeared for January Session, Using the Formula (100-your score)* 1,45,386 / 100- Your Expected rank

As a total No. of 1,45,386 candidates had appeared for January Session, Using the Formula (100-your score)* 1,45,386 / 100- Your Expected rank will be 7,385. NITs cutoff varies to Home state quota & Other state quota, With this rank the chances seems less to get a seat in NITs

As per your percentile your predicted rank will be 32k. you will get colleges as Kohlapur institute of technology, New horizon institute of technology, Thane.

If you apply through state quota there will be chace that you will get DTU.

Hello krish

Well, it's very difficult as of now,to predict the cutoff for JEE mains paper 2 based on percentile.You can first calculate your rank by rank=(100-percentile)*145386/100.With this rank,you can compare previous year's cutoff for different colleges and can predict some of the colleges you may be getting.But remember this

Hello janardhan,

On the basis of the rank only the cutoff for college is decided. U can expect it to vary after the NTA releases the final result post the April session.We can't predict the college.You can go for college predictor which Colleges are available for your percentile.

You can