SPA Delhi All Questions

Hello aspirant,

According, to your percentile score your rank will be around 960 which is a pretty good rank to get a seat in any Architecture college in India.
I will mention castewise closing ranks to get a seat SPA,Delhi -

• General- 414
• OBC- 205(category rank)
• SC- 52(category rank)
• ST-

Hello,

You have not mentioned your category.Please mention it.However, your expected rank can be calculated by the formula (100-your total percentile)*112679/100.By calculating your rank will be around 247.So by considering 2019 cut off you will have good chances of getting SPA,Delhi.The cut off was as follows in 2019 for B.arch

Hey there hope you're doing well.
Dear aspirant, yes there is a scope for diploma students for admissions at NITs IITs and SPAs but for that they need to appear for the JEE MAIN &ADVANCED examinations. There is no age limit for appearing in JEE MAIN examination but the candidate

Hey there hope you're doing well.
Dear aspirant, according to your percentile score in JEE MAIN examination paper 2 your expected rank is about 10,141 in open category. The previous year cut off in architecture stream at SPA DELHI for OBC category was opening rank-643 &closing rank-1175.
If your category

Hello Sarthak

As you have mentioned your percentile your expected rank should be 6005 and with this rank,there are chances that you will get NITs or SPA.But you have to wait for the official cut off and also you can check last year cut off here https://engineering.careers360.com/articles/jee-main-cutoff-for-b-arch-b-planning

However if you

Hey there hope you're doing well.
Dear aspirant; according to your percentile score in JEE MAIN examination paper 2 your expected rank is about 3,177. With this rank you can easily secure a seat in SPA BHOPAL as cutoff for b.planning at SPA Bhopal is 3,214 as per previous year

Hi  Supreeth,

You got 93.408 percentile in JEE main 2 exam, your rank would be approximately in between 7000 to 8000.  Also, Above is the range of your possible rank. The predicted rank may vary due to JEE Main tie breaker rules for the same score. Also, you can check

You can calculate your rank in JEE Main Paper 2 using the formula:

Rank = (100-percentile)*(No. of students appeared for the examination)/100

As the no. of students appeared for Paper 2 (Jan) are around 112679, your rank will be around 1250. However as the no. of students in April changes,

Hi dear,

You have scored 99.22 percentile in JEE main paper 2 that means your rank should be around 878. You can also calculate your rank as

Rank=(100-your percentile)×112679÷100

Last year cutoff of spa Bhopal was around 808. You can check here

https://www.google.co.in/url?q=https://www.careers360.com/colleges/thakur-college-of-engineering-and-technology-mumbai/cut-off&sa=U&ved=2ahUKEwjilvGQ56XnAhUS63MBHUOYBjkQFjAEegQIBxAB&usg=AOvVaw17FFO0-OfebnAr6UMCpMUX

Hope it helps.

Hello Vikas

Last years cut off for SPA bhopal for b. Arch for general category opening and closing rank are as follows:

Opening rank was 183 and closing rank was 870 for general category.

Admission in its undergraduate courses, B.Arch. and B.Plan. will be given on the basis of JEE