SPA Delhi All Questions

You can calculate your rank in JEE Main Paper 2 using the formula:

Rank = (100-percentile)*(No. of students appeared for the examination)/100

As the no. of students appeared for Paper 2 (Jan) are around 112679, your rank will be around 1250. However as the no. of students in April changes,

Hi dear,

You have scored 99.22 percentile in JEE main paper 2 that means your rank should be around 878. You can also calculate your rank as

Rank=(100-your percentile)×112679÷100

Last year cutoff of spa Bhopal was around 808. You can check here

https://www.google.co.in/url?q=https://www.careers360.com/colleges/thakur-college-of-engineering-and-technology-mumbai/cut-off&sa=U&ved=2ahUKEwjilvGQ56XnAhUS63MBHUOYBjkQFjAEegQIBxAB&usg=AOvVaw17FFO0-OfebnAr6UMCpMUX

Hope it helps.

Hello Vikas

Last years cut off for SPA bhopal for b. Arch for general category opening and closing rank are as follows:

Opening rank was 183 and closing rank was 870 for general category.

Admission in its undergraduate courses, B.Arch. and B.Plan. will be given on the basis of JEE

Hey there hope you're doing well.
Dear aspirant, congratulation on scoring a good percentile in the JEE MAIN examination paper 2 for B.arch. As per your percentile you are in the top 2 percentile of students but still cutoffs for paper 2 is very high. You can calculate your rank

Hey there hope you're doing well.
Dear aspirant, you're at right place for we can provide you with formula for calculating your rank with your percentile score in JEE MAIN examination paper 2.
Formula ( 100- your percentile score)112679/100
Also I'm providing you with our college predictor link to get

Hello Shruthi

As you have mentioned your percentile in JEE MAINS PAPER 2,your expected rank should be 13,127,and with this rank you cannot get NIT because the cut off of NITs is very high,you can check previous year cut off here https://engineering.careers360.com/articles/jee-main-cutoff-for-b-arch-b-planning But don't worry,because there are many other colleges

Hello.
You can calculate your expected AIR by using the formula given below:
(100-your total percentile)*112679/ 100
Here 112679 is the number of candidates appeared for the exam in January 'session'.
Using above formula you can calculate your expected AIR which would be : 496.
But in SPA delhi as

Hello

It would be difficult to tell you exactly about the cutoff as it varies every year depending on many factors such as the difficulty level of the exam, number of candidates appearing in the exam, number of seats, etc.

You can refer to the previous year cutoff for reference

Looking towards your percentile score which is 93.408. ..
Your rank can be predicted by the following method:
First of all you need to get the percentage of people ahead of you-
(100- your score).
100-93.408 = 6.592
The number of candidates appeared for January exam were 112679
And the

Rank in JEE Main Paper 2 can be calculated by the formula:

Rank = (100-percentile)*(No. of students appeared for the examination)/100

As the no. of students appeared for Paper 2 are 112679, your rank will be around 19000. However as the no. of students in April changes, your rank will