SPA Delhi All Questions

Hello Shruthi

As you have mentioned your percentile in JEE MAINS PAPER 2,your expected rank should be 13,127,and with this rank you cannot get NIT because the cut off of NITs is very high,you can check previous year cut off here https://engineering.careers360.com/articles/jee-main-cutoff-for-b-arch-b-planning But don't worry,because there are many other colleges where you can get admission.

You can use college predictor tool to get the result of colleges you can get at this rank from here https://engineering.careers360.com/jee-main-architecture-college-predictor

I hope This Helps

Best Of Luck!!!!

Hello.
You can calculate your expected AIR by using the formula given below:
(100-your total percentile)*112679/ 100
Here 112679 is the number of candidates appeared for the exam in January 'session'.
Using above formula you can calculate your expected AIR which would be : 496.
But in SPA delhi as per the past trends we can analyse that cutoff for general  category goes nearly under 480 ( average for b.arch) and for b.plan it goes nearly under 1200( average ) so , you have decent chances of admission in both if we consider your category .
Now for predicting more college you can refer our college predictor tool from the below link:
https://engineering.careers360.com/jee-main-college-predictor
Best of luck.

Hello

It would be difficult to tell you exactly about the cutoff as it varies every year depending on many factors such as the difficulty level of the exam, number of candidates appearing in the exam, number of seats, etc.

You can refer to the previous year cutoff for reference and to have an idea about the rank required. Last Year's cutoff for admission to Architecture course in School of Architecture and Planning, New Delhi was as follows:

For OBC NCL, Closing rank (round 7) was - 733
For Open category, Closing rank (round 7) was - 768

Good Luck!

Looking towards your percentile score which is 93.408. ..
Your rank can be predicted by the following method:
First of all you need to get the percentage of people ahead of you-
(100- your score).
100-93.408 = 6.592
The number of candidates appeared for January exam were 112679
And the formula to predict your rank is
(100 - your total score) 112679/100
6.592 1126.79 = 7427..
You might get good College in your home state Karnataka..
You can go through the given link to know about which college you might be getting by entering your predicted rank...
https://engineering.careers360.com/jee-main-architecture-college-predictor

Rank in JEE Main Paper 2 can be calculated by the formula:

Rank = (100-percentile)*(No. of students appeared for the examination)/100

As the no. of students appeared for Paper 2 are 112679, your rank will be around 19000. However as the no. of students in April changes, your rank will change according to that.

With this rank there are very less chances of getting a NIT. You may apply to other colleges offering Architecture branch.

You can check the last years' B.Arch cutoffs using the link given:

https://engineering.careers360.com/articles/jee-main-cutoff-for-b-arch-b-planning

To check the list of colleges which you may get with this percentile, kindly use the colleges predictor through the link provided below:

https://engineering.careers360.com/jee-main-architecture-college-predictor

Hello,

We can use the below formula to calculate your approximated rank

100 - your total percentile score is the percentage  of people ahead of you. 112679 are the number of candidates appeared for January exam.

So rank formula is (100 - your total score) X 112679 /100.

Your expected rank will be around 3042.

But the last year cut off was 733 for OBC. So you may not get into SPA delhi

You will have to clarify regarding any fee or reimbursement with the college authority directly. Usually when the student has already paid the fee and later he or she provides a suitable fee waiver or a similar document, the college is expected to process a refund. But the rules and regulations vary from college to college.

Hi Satyam.

The minimum marks required to get into SPA Delhi for an OBC (Other Backward Castes) candidate are -

• 302 Max. Closing rank and around 733 marks in 2018 for BArch,
• 949 Max. Closing rank afor BPlan in 2018.

Previous year last round cut off by rank was 768 for general, 733 for OBC, 218 for SC, 65 for ST.

SPA Delhi cutoff of JEE Main paper 2 score for admission are as follows :-

Category                                            Opening rank                       Closing rank

General                                                         7                                          414

OBC                                                              79                                         205

SC                                                                 23                                          52

ST                                                                   9                                           34

Hii Dinesh!
The cut-offs vary every year accordingly and you have to work really hard to get above 350 in Jee Mains in order to get admissions. The tips to prepare are -
*Know your syllabus well
*Make a time table and follow it well
*Solve as many question banks as you can
*Make small notes and revise regularly
*Clear your doubts regularly

You can even join the preparation packages provided by careers360 and prepare for the exam. The link is provided below -
https://learn.careers360.com/knockout-jee-main-april/

You can refer the following link as well to get more information -

https://www.google.com/amp/s/engineering.careers360.com/articles/jee-main-cutoff-for-b-arch-b-planning/amp

Hope this helps.
Good luck!