IIIT Delhi All Questions

Hi Bankuru,

According to the formula (100 - your total score) X 869010 /100 your expected rank is coming out to be AIR 14608 and it will vary as the number of students writing the April attempt are expected to increase.

2018 Cutoff for IIIT Delhi, CSE branch for OBC category was AIR 57512.

Now, you have got much more higher rank than this so congrats, you will surely get a seat in IIIT Delhi CSE Branch.

If you are interested in knowing colleges for which you are eligible then you should go to the link mentioned below.

Link - JEE Main College Predictor

Hope it helps you.

Good Luck!

Hi,

Hope your are doing great!

As per your percentile your ranking will be as follows:

100-(percentile obtained)×no. Of students appeared ÷100=

100-98.319×869010÷100=

14608.

It's difficult to get seat in both of these NITs as their cutoff is high comparative to other NITs .

For a clear picture ,click on the link provided below to know more about cutoff https://engineering.careers360.com/articles/nits-cutoff-for-top-btech-branches/amp

For college prediction , use the following link to know, in which college or NITs you may get into by this percentile:

https://www.careers360.com/college-predictor

Hi there,

From research, for getting in IIT Delhi, you have to get atleat the percentage of 85% and above in OBC category and rank should be inside one lakh in the JEE results.

You can calculate your rank using 100 - your total NTA score × 869010/100 and if the number of candidates are increasing then 100 - total NTA cost × 12,00000/100.

Hope thia will help you.

Thank you

You can calculate your rank in JEE Main Paper 1 using the formula:

Rank = (100-percentile)*(No. of students appeared for the examination)/100

As the no. of students appeared for Paper 1 (Jan) are around 869000, your rank will be around 199000. However as the no. of students in April changes, your rank will change according to that.

With this rank, there are very less chances of admission into IIIT-D. You can visit the official website to check the last years' cutoffs or may use the following link:

https://www.iiitd.ac.in/admission/btech/cutoffs18

For more information regarding counseling, cutoffs, etc.. you can use the B.Tech companion from the link given below:

https://www.careers360.com/btech-companion

Hi Abhishek,

Its difficult to predict actual rank or JEE advanced qualify marks. you may calculate your expected rank by this formula

To Calculate the rank for B. Tech:
So Rank Formula is (100 - your total score) X 1200000/100.

Your predicted JEE Main AIR rank for 2020 is
231785-243985

You will not be able to take addmission in IIIT Delhi on this score.


I hope you will increase your nta score in April and take admissions in nit or iiit

Hope this helps! All The Best!!

Feel free to ask if you have any more queries

Hello aspirant,

You can calculate your rank using the below formula-
100 - your total percentile score is the percentage  of people ahead of you. 869010 are the number of candidates appeared for Jan exam. So rank formula is (100 - your total score) X 869010 /100.

Based on your percentile score your rank will be around 53,000.
You have a chance of getting a seat in NSIT.

Hope this helped you.

Hello Dear You scored well in the paper.
Its difficult to predict actual rank or JEE advanced qualify marks. you may calculate your expected rank by this formula

100 - your total percentile score is the percentage of people ahead of you. 869010 are the number of candidates appeared for Jan exam. So rank formula is (100 - your total score) X 869010 /100. If the number of candidates for April exam increased to 1200000 then your final rank shall be (100 - your total score) X 1200000/100

Its difficult to tell exact qualifying marks for jee advanced eligibility but if you are getting more than 85 percentile score then you have decent chances to qualify for jee advanced
You can have a look to college predictor , it will be helpful to you in finding your college.

Wish for your bright future.https://engineering.careers360.com/jee-main-college-predictor

Hey,


According to your score, you can expect your rank to be around 2,52,012. You can calculate your rank using the formula:
(100- your percentile)869010/100.

Here, 869010 is the number of students who appeared in January session. If the number of candidates change in April session, then the rank will also change.
With this rank, it is quite difficult to get admission in IIIT Delhi or IIIT Allahabad. Though, you might get admission in IIIT Delhi. We don't have category specific rank yet, but category also plays an important role in determining admission.

IIIT Delhi 2019 cutoff was around 3 lacs for home state Candidates, but for other states it was around 4000-5,000.

Kindly use our College predictor to see your possibilities:
https://engineering.careers360.com/jee-main-college-predictor

Hope this helps!

Hello Satwik,

Congrats for getting good percentile. You will be selected for Jee advanced, and if you get good marks in jee advanced then you can get seat in IIT. With the percentile of jee main we only can estimate either you will be in an NIT or not. But we can only say about IIT after you have written jee advanced. Prepare well for advanced. Wish you luck.

Hello

According to your percentile, you have chances to get a seat in Mechanical Engineering, Instrumentaion and Control Engineering in Netaji Subhas University of Technology, Electrical Engineering, Civil Engineering in DTU, ECE, Computer science and Biosciences in IIIT Delhi. Use the JEE Main College Predictor Tool to check the other engineering branches which you can get based on your percentile

https://engineering.careers360.com/jee-main-college-predictor

Good Luck!