Nanhi Pari Seemant Engineering Institute, Pithoragarh All Questions

Dear student,

The Consortium of National Law Universities conducts Common Law Admission Test (CLAT). It is a pen & paper based exam. If you can complete your graduation before the start of CLAT 2023 admission then you can appear for CLAT 2022 exam in December after completion of Bachelor's degree in LLB in August 2023. Candidates who are in final year of graduation or who have completed their graduation can appear for CLAT exam.

It is a pen & paper based exam. You can visit their official website for more information consortiumofnlus.ac.in.

Number of seats available are - CLAT-based seat Intake: 5-year integrated LLB program - 2538 seats and LLM program - 742 seats.

There will be 150 MCQs for UG CLAT & 120 MCQs for PG CLAT exam in 2023. 22 National Law Universities will be participating in CLAT 2023.

To get more information about CLAT 2023 Important Dates, Eligibility Criteria, Prepration Tips, etc go through below mentioned link.

https://law.careers360.com/articles/clat-2023-exam-date-eligibility-syllabus-pattern-seats-preparation-tips/amp

May this information helps you.

Best of Luck!!

Hello Aspirant,

Hope you are doing great. A Graduate Degree from a recognized university is required for the candidate. UPSC Civil Services Exam Age Limit: Candidates must be at least 21 years old and no older than 32 years old. A Graduate Degree from a recognized university is required for the candidate. UPSC Civil Services Exam Age Limit: Candidates must be at least 21 years old and no older than 32 years old.

As of April 2023 you will be 21 years old and there fore you can give you exam thereafter and you should have a degree as basic from any stream.

ALL THE BEST

Hi Aspirant,

Hope you are doing great as per the question asked by you,as you are going to give 12th board examination in 2023 and want to appear for N.E.E.T 2022 so it is not possible as firstly you need to be appearing candidate or should have passed class 12th examination then only you would be eligible for N.E.E.T.

Hope you found this answer useful. Stay motivated stay positive.

All the best!

If you want to go for the course of Architecture, then you have to appear for the JEE MAINS paper 2. Now the JEE MAINS paper-2 isn't actually the same as that of the JEE MAINS paper-1 for Engineering.

The JEE MAINS paper-2 is divided in three sections. The part-1 consist of Mathematics, Part-2 consist of General Aptitude and the part-3 consist of Drawing. So as you can see only the Mathematics section matches with the paper-1.

The syllabus of Mathematics is provided below for JEE MAINS paper-2:

• Complex numbers and quadratic equations

• Matrices and determinants

• Sets, relations and functions

• Mathematical induction

• Permutations and combinations

• Mathematical reasoning

• Limit, continuity and differentiability

• Integral calculus

• Three-dimensional geometry

• Differential equations

• Binomial theorem and its simple applications

• Sequences and series

• Vector algebra

• Statistics and probability

• Trigonometry

• Coordinate geometry

So if you wish to go for the JEE MAINS paper-2 then it would be better for you to prepare for it separately.

For more information regarding the JEE MAINS paper-2 consider the link below:

https://engineering.careers360.com/articles/jee-main-paper-2-syllabus

I hope this helps. Wish you a great day!

Hello aspirant,

Looking at the previous year SRMJEE Cutoff trends and analytics, You have good chances to get CSE (Computer Science and Engineering ) branch in SRM Chennai branch as the previous year closing Cutoff for SRMJEE CSE branch goes up to 9000-10000. So, you have good chances to get SRM Chennai branch.

Further, please note that the Above prediction is solely based on the Previous year SRMJEE Cutoff and it may vary as the SRMJEE cutoff varies for every year. Further, the SRMJEE Cutoff depends on various factors like : Number of aspirants appearing, Previous year cutoff trends, difficulty level of the paper, etc.

I would suggest you that you must sit in the counselling as 4K in SRMJEE phase 2 is also a good rank. Further, you can also prepare for some other engineering exams like MHTCET, JEE Mains, etc. of your choice.

Further, if you wish to know more about the Previous year and expected SRMJEE Cutoff, you can follow the below mentioned link to know more : https://engineering.careers360.com/exams/srmjeee

https://engineering.careers360.com/articles/srmjeee-cutoff

I hope that this will help.

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Hi

Assuming you from general category.

No, you will not eligible for UPSC 2024 examination.

This is because,

For general category, upper age limit is 32 years old as on 1st of August of the year of filling the form i. e means to be eligible you should not be more than 32 years old on 1st August 2024 in case of UPSC 2024

But with your mentioned date of birth , you will be more than 32 years old i. e 32 years and 6 months  old as on on 1st August 2024 and  thus not eligible for UPSC 2024

But if you belong to obc, sc, st then you are eligible

For reference,

UPSC eligibility  criteria is provided below:-

********   You  must  have  a  bachelor's  degree in any, discipline    from a  recognised university   .

******** Minimum  age  limit :-  you  need to  be at least  21  years  old   to be  eligible as on 1st of August of the year of filling the form

******** Maximum  age  limit :-as on 1st August of the year of examination

• General category :-32 years

• Obc :- there's 3  year  relaxation on upper age limit for  obc , so upper age limit is 35.

• Sc/st :- 5 years relaxation, so upper age limit is 37.

********Attempt limit:- The maximum of times one can appear in UPSC is given below category wise :-

• General/ EWS - 6

• OBC or  General PwD - 9

• SC/ ST - No limit ,   can appear till upper age limit .

For detailed  information related to UPSC eligibility criteria ,  you can visit our page at

https://competition.careers360.com/articles/upsc-ias-eligibility-criteria/amp

Thank you

hello aspirant,

see technical placement is for those who are doing btech or mtech in iit kharagpur. and from bsc in chemistry you are not eligible to apply for technical job. however after doing msc from iits many candidates of chemistry honours get placed in many industry, cosmetic company, fmgc companies.

Hello Aspirant,

No you cannot appear for NEET UG because to become eligible for NEET UG one should have Physics and Biology compulsorily in his/her curriculum and you don't have Physics so you are not eligible for NEET UG.

For your reference I am mentioning down the eligibility criteria of NEET UG 2022.

To appear in NEET UG you need to satisfy some eligibility conditions :-

For 10+2 or equivalent :-

>>>>> You need to pass separately in theory as well as in practical of PCB.

>>>>> If you belongs to General/UR category then your aggregate of PCB (Theory + Practical) should be equal to or more than 50%(40% for SC/ST/OBC and 45% for PwD).

>>>>> You should be pass in English subject as well.

So if you satisfy all above conditions then you are eligible for NEET UG 2022 with respect to the criteria of marks.

Complete NEET UG ELIGIBLITY CRITERIA :-

** You must have passed 10+2 from any recognized central/state board.

** English should also be in your curriculum of class 12th and also you should have passed in it.

** You minimum age should be more that or equal to 17 years by December 31st 2022, as per the current eligibility criteria.

** Now there is no upper age limit for NEET UG.

For complete details about NEET UG Eligibility criteria kindly check out the link given below :-

https://medicine.careers360.com/articles/neet-eligibility-criteria

If you are preparing for NEET then to help you in your preparation we have some resources which you can access from the link given below :-

https://learn.careers360.com/knockout-neet-may

I hope this information helps you.

Good Luck!!

hello aspirant,

On the above percentile score, it is really difficult for you to get any branch in KIITEE as your percentile score is likely to be very low. Further, the category wise Cutoff percentage for getting any branch in KIITEE is mentioned as follows :

General - 50%

ST/SC/OBC - 40%

PwD (General) - 45%

Further, if you wish to know more about the KIITEE cutoff percentage for previous years you can follow the below mentioned link to know more : https://university.careers360.com/articles/kiitee-cutoff

https://www.careers360.com/exams/kiitee

I hope that this will help.

Hello aspirant,

Since you have not mentioned your category , I am considering you as a GENERAL Category Student. Now, Looking at the previous year JEE mains Cutoff trends and analytics, to get admission in IIIT Hyderabad, you need to get 270+ marks in JEE mains to get into IIIT Hyderabad.

The authorities accepts applications for IIIT Hyderabad B. Tech admission 2022 on the basis of four modes - JEE Main, DASA, UGEE/SPEC and Olympiad/KVPY . Candidates will be able to choose their preferred mode of admission as per their eligibility.

Further, Note that the above prediction is solely based on the previous year IIUT Hyderabad Cutoff and trends which may vary also. The JEE mains cutoff vary for every year and it bound to change every year, as it depends on several factors like : Difficulty level of the paper, previous year trends, number of aspirants appearing, etc.

Similar is also for UGEE Exam. As per the previous year, the cutoff marks for an interview call for the UGEE mode (eligible for dual degree programmes) was 104 marks . You should try to solve at least 80% of the queries.

Further, if you wish to know more about the JEE mains IIIT Hyderabad previous year Cutoff trends you can follow the below mentioned link to know more : https://engineering.careers360.com/articles/iiit-hyderabad-btech-cutoff

https://engineering.careers360.com/articles/jee-main-cutoff

Further, you can also check your admission chances based on teh rank scored in JEE mains with the help of JEE mains college predictor tool mentioned below : https://engineering.careers360.com/jee-main-college-predictor?utm_source=qna&utm_medium=jee_cp

I hope that this will help.