College of Engineering, Trivandrum All Questions

Hello Bhushan,

Candidates must have passed 10+2 or equivalent exam in any stream from a recognised Board or College.

There are Colleges which admission only based on entrance exam and there are also Colleges which gives admission based on merit as well.

Best Colleges in Maharashtra accepting admission without entrance exam as well.

Sandip University, Nashik, Maharashtra

Mit World Peace University, Maharashtra

NMIMS School of Law, Maharashtra

Indian Law Society Law College, Maharashtra

Gondwana University School of Law, Maharashtra

Shankarrao Chavan Law College, Maharashtra

Ajeenkya DY Patil University, Maharashtra

Sinhgad Law College, Maharashtra

Tilak Maharashtra University, Maharashtra

Hope this information was helpful to you.

Good Luck!!

Hello,

To predict your rank you can use Rank Predictor provided by career360. You need to follow the following steps:

1. Visit the Careers360 CET 2022 rank predictor webpage.
2. Enter required details i.e. scores and application number in the column specified.
3. Click on the “Predict My Rank” button.
4. The CET 2022 rank will be displayed on the screen.

You can use it for MHT, KCET, etc.

Hope it helps you.

Hello,

From your profile it seems you're a law aspirant and belong to Maharashtra, hence I assume your query is pertaining to MHT CET LAW,

You can check out previous year paper of MHT CET LAW by visiting our page at https://engineering.careers360.com/articles/mht-cet-sample-papers,

this will make you familiar with the pattern of the examination, marking scheme, important topics, weightage etc,

through consistent practice you can analyze your level of preparation in terms of  strength and weakness, and improve your speed, calculation, and time management skills.

Hello,

As of now it is possible to know the estimated rank as there are various factors that determine the rank such as marks scored in KCET, Normalized marks, marks scored in qualifying examination that is 10+2 etc. The marks scored in qualifying examination and KCET will be combined to determine the rank so it is difficult to predict the exact rank. Based on KCET 2022 Marks vs Rank predictor your rank is expected to be around 12,000 with the given marks out of 180 marks. The final rank may vary. You can know your rank after KEA releases the results for KCET 2022.

To check KCET 2022 marks vs rank click on the link below

https://engineering.careers360.com/articles/kcet-marks-vs-rank

Hello Aspirant,

It is quite difficult to predict the exact rank based on your given marks because the rank Vs marks keeps on changing depending upon various factors such as :

** Number of candidates appeared for examination.

** Top score for that particular year.

** Total number of seats available.

And some more factors, therefore your actual rank in KCET 2022 might vary with slight variations.

As per the marks mentioned by you in the question your rank in KCET 2022 is expected to be in the range of  40000-50000 .

But note that this is not your exact rank because it is not yet released and the rank predicted above is on the basis of previous year's data.

You can use KCET 2022 College Predictor toll to predict the colleges that you can get based upon your KCET 2022 rank. You can use KCET College predictor from the link given below :-

https://www.careers360.com/kcet-college-predictor?icn=QnA&ici=qna_answer

I hope this information helps you.

Good Luck!!

The earlier date of MH CET LAW application form was 24 March 2022. Later it was extended to 22nd June 2022 by Maharashtra state due to public demand. However, the extended date has also passed now and it is not possible for the aspirants to apply for the same anymore.

Hello aspirant,

Hope you are doing absolutely great.

So with regard to your query, in order to get a rank as and below 10000, in the KCET exam, one need to score between 100 to 110 marks out of 180 marks for getting the engineering course.  Because the cutoff varies from one year to the other basing upon the level of the exam.

Hope this helps you!!

Hello aspirant,

Hope you are doing absolutely great.

So with regard to your query, in order to get a rank as and below 10000, in the KCET exam, one need to score between 100 to 110 marks out of 180 marks. Because the cutoff varies from one year to the other basing upon the level of the exam.

Hope this helps you!!

Hello Aspirant,

Your EXPECTED RANK in KCET 2022 :-

>>>>>> 60000+

But note that this is not your exact rank because it is not yet released and the rank predicted above is on the basis of previous year's data.

As the rank Vs marks keeps on changing depending upon various factors such as :

** Number of candidates appeared for examination.

** Top score for that particular year.

** Total number of seats available.

And some more factors, therefore your actual rank in KCET 2022 might vary with slight variations..

You can use KCET 2022 College Predictor toll to predict the colleges that you can get based upon your KCET 2022 rank. You can use KCET College predictor from the link given below :-

https://www.careers360.com/kcet-college-predictor?icn=QnA&ici=qna_answer

I hope this information helps you.

Good Luck!!

Hello Aspirant,

It is quite difficult to predict the exact rank based on your given marks because the rank Vs marks keeps on changing depending upon various factors such as :

** Number of candidates appeared for examination.

** Top score for that particular year.

** Total number of seats available.

And some more factors, therefore your actual rank in KCET 2022 might vary with slight variations.

As per the marks mentioned by you in the question your rank in KCET 2022 is expected to be in the range of  3500-4000 .

But note that this is not your exact rank because it is not yet released and the rank predicted above is on the basis of previous year's data.

You can use KCET 2022 College Predictor toll to predict the colleges that you can get based upon your KCET 2022 rank. You can use KCET College predictor from the link given below :-

https://www.careers360.com/kcet-college-predictor?icn=QnA&ici=qna_answer

I hope this information helps you.

Good Luck!!