Amity University Noida-B.Tech Admissions 2026
ApplyAmong top 100 Universities Globally in the Times Higher Education (THE) Interdisciplinary Science Rankings 2026
Hello. You have a good percentile. It means that 6% of tot students appeared in the exam are ahead of you. (Approx Tot. Students appeared- 874469).
Though it is difficult to predict the cutoff for any particular college now but any rank below 2,00,000 might get you qualified for JEE
HELLO PANKAJ
YOU CAN WAIT FOR THE THE FINAL SCORE TO BE ANNOUCED BY NTA.
FOR THE TIMING WE CANT MAKE ANY ASSUMPTION BASED UPON YOUR PERCENTILE.
IF YOU WANT YOU CAN PREDICT YOUR EXPECTED YOUR RANK USING THE LINK BELOW
https://engineering.careers360.com/jee-main-college-predictor
HAPPY LEARNING!!
Hi there.
The final cut off list will be declared by NTA after the April session of the JEE mains examination.
As for now, your probable rank can be calculated.
Now, A total of 874469 candidates wrote the exam. Since the percentile is calculated from a scale ranging from 100
Hello
It is difficult to predict the actual rank or JEE Advanced qualifying marks as for the first time JEE Main is being conducted twice and rank will be based on NTA percentile score.
You may calculate the expected rank by this formula-
874469 are the number of candidates appeared
Hello gaddam!
jee advanced minimum percentile qualification is 70 percentile as declared by the NTA.
The nit admission minimum qualification percentage in class 12 is
General category - 75%
Sc/st category - 65%
Or the top 20 percentile in the class 12 exam conducted by your respective boards.
Hello Navyasri..
Percentile= (marks you got*100)/(toppers marks in that session).
According to careers360 rank formula,
Rank formula= [(100-total score) * (no of students wrote exam)] /100
No of students attended are 874469.
So your expected rank will be nearly around 1,05,933.
As per previous year jee mains, any rank below
Hey raushan!
The best way to calculate the rank is using the below formula.
Rank = total no of students--percentile×0.01×number of students
The minimum percentage qualification for nit for general category is 75%
And sc/st category is 65%
Wish you all the best
The infrastructure is well maintained with functional classrooms, decent labs and necessary facilities. while not luxurious, it comfortably supports academic and student activities very well. it is well arranged
Our college Narula institute of technology , Agarpara has provided us with a strong , safe environment along with all the necessary facilities including spacious classrooms , libraries stocked with proper curriculum based books clean and hygienic cafeteria . our college provides with a strong wi-fi system along with other electronic facilities including smart boards , projectors and also CCTV cameras which again provide security , even our labs are well equipped with gadgets and tools use for practical purposes .
Our college provides us will all the necessary amenities that we require for a healthy environment to study in especially spacious classrooms proper benches and digital boards. Our labs are fully equipped with modern tools making practical learning smooth, engaging, and genuinely helpful across all subjects. The campus feels safe, clean and reliable with well maintained CCTV cameras, hygienic environment and secure and attentive staffs looking out for us. In short our campus is easy to navigate and comfortable to access.
Among top 100 Universities Globally in the Times Higher Education (THE) Interdisciplinary Science Rankings 2026
Last Date to Apply: 29th April | Ranked #43 among Engineering colleges in India by NIRF | Highest Package 1.3 CR , 100% Placements
Among top 100 Universities Globally in the Times Higher Education (THE) Interdisciplinary Science Rankings 2026
Recognized as Institute of Eminence by Govt. of India | NAAC ‘A++’ Grade | Upto 75% Scholarships
Last Date to Apply: 26th April | NAAC A++ Accredited | NIRF Rank #3
India's youngest NAAC A++ accredited University | NIRF rank band 151-200 | 2200 Recruiters | 45.98 Lakhs Highest Package