It's a Question of your Career!

Correct Answer: 25

Solution : Given:

Y² : 4 :: V² : ?

Here, (Y)² = 2² = 4.

So, (V)² = 5² = 25.

Hence, second option is correct.

Correct Answer: 12%

Solution : Let $R$ be the rate of interest.
Simple interest = $\frac{\text{Principal × Rate × Time}}{100}$
Simple interest on INR 2,500 after 3 years = $\frac{2500×3×R}{100}$
Simple interest on INR 1,500 after 3 years = $\frac{1500×3×R}{100}$
According to the question,
$\frac{1500×3×R}{100}$ + 360 = $\frac{2500×3×R}{100}$
⇒

Correct Answer: 12%

Solution : Let $R$ be the rate of interest.
Simple interest = $\frac{\text{Principal × Rate × Time}}{100}$
Simple interest on INR 2,500 after 3 years = $\frac{2500×3×R}{100}$
Simple interest on INR 1,500 after 3 years = $\frac{1500×3×R}{100}$
According to the question,
$\frac{1500×3×R}{100}$ + 360 = $\frac{2500×3×R}{100}$
⇒

Correct Answer: (51, 112, 173)

Solution : Given:
(47, 108, 169); (22, 83, 144)

In the given sets, the difference between the second and first numbers and the difference between the third and the second numbers are the same.
(47, 108, 169)→108 – 47 = 61; 169 – 108 =

Correct Answer: 2186102

Solution : Given:
28373 is coded as 4166146.

Multiply each digit of the 28373 by 2, to get the required code –
2 × 2 = 4; 8 × 2 = 16; 3 × 2 = 6; 7 × 2 = 14; 3 × 2 = 6

Correct Answer: $-\frac{2}{3}$

Solution : $5 \frac{1}{3}-\left\{4 \frac{1}{3}+\left(3 \frac{1}{3} \div \overline{2 \frac{1}{3}-\frac{1}{3}}\right)\right\}$
$=\frac{16}{3}-\left\{ \frac{13}{3}+\left( \frac{10}{3} \div \overline{\frac{7}{3}-\frac{1}{3}}\right)\right\}$
$=\frac{16}{3}-\left\{ \frac{13}{3}+\left( \frac{10}{3} \div 2\right)\right\}$
​​​​​​​$=\frac{16}{3}-\left\{ \frac{13}{3}+( \frac{5}{3})\right\}$
​​​​​​​$=-\frac{2}{3}$
Hence, the correct answer is ​​​​​​​$-\frac{2}{3}$.

Correct Answer: 65

Solution : Here, multiply the number by 2 and subtract 1 in the clockwise direction to get the next number. 
Like, 17 = 9 × 2 – 1
And, 33 = 17 × 2 – 1
Similarly, 33 × 2 – 1 = 65

So, the missing

Correct Answer: 59.58

Solution : Average speed for the same distance
= $\frac{\text{2ab}}{{\text{a+b}}}$, where a and b are the speeds
= $\frac{2\times 55 \times 65}{55+65}$
= $ \frac{2\times 55\times 65}{120}$
= $59.58$
Hence, the correct answer is 59.58 km/hr.

Correct Answer: Zone melting

Solution : The correct option is - Zone melting

Zone melting is the method used to purify metals to the highest degree. A little amount of the metal is first melted, and then it is pushed along the remaining metal while impurities are removed.

Correct Answer: 3

Solution : The correct choice is the third option.

Explanation: "Those" is a demonstrative pronoun used for distant objects, and "these" is used for comparatively closer objects. The pronoun "these" is appropriate here because it refers back to the plural noun "rules". Since "rules" is plural,