Question : A conical tent of height 10 m and base diameter 48 m was erected by a company in a park. Find the curved surface area of the tent (in m2).
Option 1: $576 \pi$
Option 2: $1248 \pi$
Option 3: $1152 \pi$
Option 4: $624 \pi$
Correct Answer: $624 \pi$
Solution :
A conical tent of height 10 m and base diameter 48 m was erected by a company in a park.
Here base radius ($r$) = $\frac{48}{2}=24$ m and height ($h$) = 10 m
Let the slant height = $l$ m
Now, $l^2=h^2+r^2$
⇒ $l^2=10^2+24^2$
⇒ $l=676$
⇒ $l=26$ m
$\therefore$ The curved surface area of a tent = $\pi×r×l=\pi×24×26= 624\pi$
Hence, the correct answer is $624\pi$.
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