#SSC CGL

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Question : If $(4a-3)^2=0$, then the value of $64a^3-48a^2+12a+13$ is:
Option 1: 0
Option 2: 11
Option 3: 22
Option 4: 33

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Team Careers360 24th Jan, 2024

Answer (1)

Team Careers360 25th Jan, 2024

Correct Answer: 22

Solution : Given: $(4a-3)^2=0$
$⇒4a-3=0$
$⇒a=\frac{3}{4}$
Substitute the value of $a$ in the equation below, we get,
$64a^3-48a^2+12a+13$
$=(4a)^3-3×(4a)^2×1+3×4a×(1)^2-(1)^3+14$
$=(4a-1)^3+14$
$=(4×\frac{3}{4}-1)^3+14$
$=8+14$
$=22$
Hence, the correct answer is 22.

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