I score 96.03 percentile for jee paper 2.with this score can I get admission into Nit's.i am obc category
JEE Main 2026 Session 2: Result Link | Final Answer Key
JEE Main 2026: College Predictor | Official Question Papers
Comprehensive Guide: IIT's | NIT's | IIIT's | Foreign Universities in India
Don't Miss: India's Best B.Tech Counsellors in your city - Book Your Seat
Rank in JEE Main Paper 2 can be calculated by the formula:
Rank = (100-percentile)*(No. of students appeared for the examination)/100
As the no. of students appeared for Paper 2 are 112679, your rank will be around 4500. However as the no. of students in April changes, your rank will change according to that.
With this much rank, you will be eligible to get admission in NITs in B.Arch branch. As the cutoffs for B.Arch are not that much high, you will easily get B.Arch branch in one of the top NITs.
1 like
Related Questions
Know More about
Joint Entrance Examination (Main)
Answer Key | Eligibility | Application | Result | Preparation Tips | Question Paper | Admit Card | Accepting Colleges
Get Updates Brochure
Your Joint Entrance Examination (Main) brochure has been successfully mailed to your registered email id “”.
