Hi

Hope you are doing well

Yes there is strong chance of getting admission into the B.Arch program at NIT Bhopal (Maulana Azad National Institute of Technology).

Some steps you should follow like:

• Stay Updated: Keep an eye on the official NIT Bhopal website or the JoSAA portal for the latest cutoff trends.
• Participate in Counseling: Make sure to register for JoSAA counseling, as that's how you can secure your seat.

hope this will help you for better analysis:

JEE B.Arch College Predictor

https://engineering.careers360.com/jee-main-architecture-college-predictor?utm_source=qna&utm_medium=jee_barch_cp

Best Wishes.

Hello Aspirant,

From the above question, it is specified as if you fail in one subject of 12th. Yes, still you can get an admission in the other colleges for graduation. The 12th fail, although no board or institution permits graduation, there are a number of courses that allow students get entry to graduation programmes even if they haven't completed their 12th grade.

But, strictly for better colleges it is important to clear the 12th.  The next year, the student will have to retake all of the Class 12 board tests. It's crucial to remember that the student's mark sheet will include the scores they received in the compartmental examinations separately.

ALL THE BEST

Correct Answer: $300(\sqrt3 - 1)$ m

Solution :
$AB$ = height of peak = 300 m
$CD$ = length of Bridge
We are given the angle of depression,
i.e., $\angle EAC = 45°$ and $\angle EAD = 30°$
⇒ $\angle ACB = 45°$ and $\angle ADB = 30°$
Now, \(In \triangle ABC\)
\(\tan\theta = \frac{P}{B}\)
\(\tan45 ^{\circ} =\frac{AB}{BC}\)
\(1=\frac{AB}{BC}=AB:BC=1:1\)
\(In\ \triangle ABD,\)
⇒ \(\tan30 ^{\circ} =\frac{AB}{BD}\)
⇒ \(\frac{1}{\sqrt{3}}=\frac{AB}{BD}\Rightarrow AB:BD=1:\sqrt{3}\)
Now,
\(CD = BD - BC\)
⇒ \(CD \Rightarrow \sqrt{3}-1\)
$AB$ = 1 unit = 300 metre
So, $CD=(\sqrt{3}-1)$ units = $300(\sqrt{3}-1)$ metres
Hence, the correct answer is $300(\sqrt3 - 1)$ m.

Correct Answer: Rs 24,000

Solution : Answer = Rs 24,000

Hence, the correct option is 3.

Hello Aspirant,

As per your JEE mains obc rank and considering the previous year cutoffs you can easily get computer science branch in nit bhopal. The cut off for previous year was 5.2k in the obc category for computer science branch.

The cut offs depends on certain factors such as number of candidates appearing in the examination, difficulty level of the paper,number of seats available in the college.