Question : If $x=a\sec\theta$ and $y=b\tan\theta$, then $\frac{x^{2}}{a^{2}}-\frac{y^{2}}{b^{2}}=?$
Option 1: 1
Option 2: 2
Option 3: 3
Option 4: 4
Correct Answer: 1
Solution :
Given: $x=a\sec\theta$ and $y=b\tan\theta$
⇒ $\frac{x^{2}}{a^{2}}=\frac{a^{2}\sec^{2}\theta}{a^{2}}=\sec^{2}\theta$
⇒ $\frac{y^{2}}{b^{2}}=\frac{b^{2}\tan^{2}\theta}{b^{2}}=\tan^{2}\theta$
The value of $\frac{x^{2}}{a^{2}}-\frac{y^{2}}{b^{2}}=\sec^{2}\theta-\tan^{2}\theta=1$
Hence, the correct answer is 1.
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