Question : In covering a certain distance, the speeds of A and B are in the ratio of 3:4. A takes 30 minutes longer than B to reach the destination. The time taken by A to reach the destination is:
Option 1: 1 hour
Option 2: 1$\frac{1}{2}$ hours
Option 3: 2 hours
Option 4: $2\frac{1}{2}$ hours
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Correct Answer: 2 hours
Solution :
Speed is inversely proportional to time.
So, $s_1:s_2 = t_2: t_1$
$s_1:s_2$ = 3: 4
$t_1: t_2 =$ 4: 3
Let $t_1= 4k$ and $t_2 = 3k$
ATQ,
$4k-3k = 30$ minutes
$k =30$
Time taken by A to reach the destination = $4k =4\times 30 = 120$ minutes = 2 hours.
Hence, the correct answer is 2 hours.
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