Question : The speed of a superfast train, T1 is 20% more than the speed of another superfast train T2. Both the trains start from point N at the same time and reach point M at the same time. N and M are 500 km apart. T1 stops for 10 minutes on the way to M, but T2 covers the distance without any stops during the entire route. What is the speed of T1?
Option 1: 600 km/hr
Option 2: 500 km/hr
Option 3: 650 km/hr
Option 4: 550 km/hr
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Correct Answer: 600 km/hr
Solution :
Distance covered = speed × time taken
Let the speed of train T
2
be $v$ and the speed of train T
1
be $1.2v$.
Let time taken for train T
2
be $t$ and the time taken for train T
1
be ($t − \frac{10}{60}$)
⇒ $vt=500$ and $1.2v(t−\frac{10}{60})=500$
⇒ $t=\frac{500}{v}$
⇒ $1.2v(\frac{500}{v}−\frac{10}{60})=500$
⇒ $600−0.2v=500$
⇒ $0.2v=100$
⇒ $v=\frac{100}{0.2}$
⇒ $v=500$ km/hr
⇒ The speed of the train T
2
is 1.2 × 500 = 600 km/hr
Hence, the correct answer is 600 km/hr.
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