Hello Sourabh

Link: https://engineering.careers360.com/articles/jee-main-cutoff-for-manit-bhopal

Maulana Azad Institute of Technology, Bhopal offers 7 B.Tech courses for the students namely Chemical Engineering, Civil Engineering, Computer Science and Engineering, Electrical Engineering, Electronics and Communication Engineering, Mechanical Engineering and Materials Science and Metallurgical Engineering. The institute has a total of 817 seats for these engineering programmes.

Hello,

You can calculate your predicted rank using the below formula

100 - your total percentile score is the percentage  of people ahead of you. 869010 are the number of candidates appeared for Jan exam. So rank formula is (100 - your total score) X 869010 /100. If the number of candidates for April exam increased to 1200000 then your final rank shall be (100 - your total score) X 1200000/100

Your predicted rank is 55616 this is the predicted rank it will change after april attempt. But the last year cut off was 3079 for home state and 2404 for other state so with your rank you will not get seat in NIT Bhopal

Hello Aspirant,

It's difficult to tell you the exact about the qualifying cutoff & admission cutoff. This score seems enough to qualify the exam but chances seems less to get MANIT Bhopal You can go for state level counselling. I would also suggest you to appear for JEE Main 2020 April Session again.

You may calculate your expected rank by this formula

100 - your total percentile score is the percentage  of people ahead of you. 874469 are the number of candidates appeared for Jan exam. So rank formula is (100 - your total score) X 869010 /100. If the number of candidates for April exam increased to 1200000 then your final rank shall be (100 - your total score) X 1200000/100

Using the formula

(100 - your total score) X 869010 /100

Your probable rank will be 85,162

You can also check your other admission possibilities to go through with the given below link.

https://engineering.careers360.com/jee-main-college-predictor

Good Luck!

• To get the percentage  of people ahead of you :

• And the number of candidates appeared for Jan exam were 869010 .
• The formula to predict rank is-

• Also if the number of candidates who apply for April attempt will increase to 1200000 then your final rank would be :

Hello

The cutoff required for admission varies every year depending on many factors such as the difficulty level of the exam, number of candidates applying for admission, etc.  You can refer to the previous year cutoff of MNIT Jaipur engineering stream wise which is as follows-

Chemical Engineering- 1311 (Home state, ST category rank)

Civil Engineering- 291
Computer Science and Engineering- 397
Electrical Engineering- 331
Electronics and Communication Engineering- 711
Mechanical Engineering- 701
Metallurgical and Materials Engineering- 3190
Architecture- 447

Good Luck!

Dear Aspirant

Your percentile is 84 it means 84 percent students are behind you in the Jee mains exam.A formula is given by nta so the formula is

No of Candidates appeared in exam/100 *(100-Nta score).The total no of can apperared in the exam was 869010

So According to this formula your rank will be 139041.

But if the no of candidates in April attempt changes to 120000 then formula will be 120000/100*(100- Nta score)

At this rank to get any nit or iiit is quite difficulty so try your best in April attempt.

You can also use college predictor to check chances of getting admiited in particular Colleges -

https://engineering.careers360.com/jee-main-college-predictor

Thanks

All the very best

Hello

Cutoff for admission to NITs is released by JoSAA. If you are seeking admission in MANIT Bhopal through JEE 2020 marks,  the cutoffs are not released yet. So, you can refer to the previous year cutoff for reference and to have an idea about the rank required for admission.
Last year's closing rank for few branches is as follows-

Computer Science Engineering
OBC : 3079
EWS : 1089
General : 8442
SC : 1957
ST : 800

Mechanical Engineering
OBC : 7858
EWS : 2724
General : 20625
SC : 5770
ST : 2132

Check the cutoff for other branches using the link below-

https://engineering.careers360.com/articles/jee-main-cutoff-for-manit-bhopal

Good Luck!

hi,

see according to students review and preferences the ranking of your choice of nits as follows,

svnit surat,

vnit nagpur,

mnit jaipur,

manit bhopal

Hello Ajay

The base capability required for induction into a confirmation course is going of the Secondary School Leaving Certificate (SSLC)/tenth standard/proportionate assessment, with in any event 35 percent in science and maths subjects.The state loads up of specialized training of the vast majority of the states in India lead passage tests.

Qualification

The base capability required for induction into a recognition course is going of the Secondary School Leaving Certificate (SSLC)/tenth standard/proportionate assessment, with at any rate 35 percent in science and maths subjects.The state loads up of specialized instruction of the vast majority of the states in India lead passageway tests for admission to the confirmation projects offered by different polytechnics in the state.

An understudy who has accomplished the recognition is typically qualified to enter B.Tech./B.E. programs in the second year under a horizontal passage plot. This most optimized plan of attack affirmation is conceivable simply in the wake of composing the LET, the Lateral Entry Test. On the off chance that you do well on this test, you can apply to B.Tech./B.E. programs.

All the best