It's a Question of your Career!

Hello,

There are four colleges in faridabad that provide M.Tech degree in mechanical engineering

• Echelon institute of technology
• Manav Rachna University
• Lingaya's Vidyapeeth
• Satya group of instutions

Please click the below link to know more about these colleges

https://engineering.careers360.com/colleges/list-of-me-mtech-in-mechanical-engineering-colleges-in-faridabad

hi,

there is only a few institute available in india which offers mca-mtech dual degree course of 4 years. I have mentioned the institute name below,

techno india university- west bengal- http://tigpublicschool.org/tiu/dual-mca-m-tech-computer-apps

Hi dear,

You have got 91 percentile in JEE main that means your rank should be 78210. Your can also calculate your rank as

Rank=(100-your percentile)×869010÷100

Your obc rank will be around 17k-18k. With this rank you have low chance to get any NIT. You can predict your college here

Hello Sujith,

After completion of your graduation you can go for the higher studies which is a better idea because:

There are plenty of opportunities which exist for the chemists in the present scenario. Almost every field in the world use chemicals as a part in some or other ways.

• KJ Somaiya Institute of Management Studies and Research Mumbai (approximately 15 Lakhs)
• Great Lakes Chennai (17.15 lakhs)
• GIM Goa (approximately 16 lakhs)
• TAPMI Manipal (14.6 lakhs)
• BIM Trichy (14.5 lakhs)
• LIBA Chennai (15.2 lakhs)
• LBSIM Delhi

hello aspirant...

The very basic eligibility criteria is that you should have completed class 10+2 or equivalent exam. Most of the colleges and universities that offer offer B.COM (//B.COM) and B.COM (//B.COM) (Hons) require you to have at least 50% or 60% marks in the 12th board exams. Admission is

Hello fnatic fc,

For the UG Programmes say B.A,B.Com,B.SC etc. the admission form will be released around 4th week of may and you need to fill and submit it by third week of june . The seats available in UG programmes such as BA, B.Com, B.Sc will be allocated on

Dear Ashwin,

NTA score is basically calculated in order to declare rank of the student.

NTA score : Normalisation in percentile in all 8 sessions.

Rank= (874469)(100-percentile/100)

According to this, (874469)(100-1/100)

Your rank will be around 865724.

According to this rank your marks would be in between 0-20 .

So,if

Hello,

3% of the seats are reserved which may likely to increase to 10% this year. Different campus are trying to improve the seat matrix for the EWS category.  there is no information about how many have applied under EWS category in different IIM campus.

if you want to know