If 2 cards are drawn from a deck of 52 card.and X = no of aces .the p(x=1)+p(x=2)
JEE Main 2026 Session 2 Memory Based Questions: All Shift (April 2, 4, 5, 6 & 8)
JEE Main 2026: Rank Predictor | College Predictor | YouTube Live Analysis - April 8 Shift 2
Comprehensive Guide: IIT's | NIT's | IIIT's
Don't Miss: Foreign Universities in India | India's Best B.Tech Counsellors in your city - Book Your Seat
P(X=1). = (4c1)*(48c1)/(52c2). ( Choose one card of the 4 aces and other one from the remaining 48 cards)
P(X=2). = (4c2)*(4/(52c2). Choose two from 4 aces.
Where c standard notation.
1 like
The total number of ways in which two cards can be drawn from the deck of 52 card is 52C2
Number of ways in which one is an Ace and other is not an Ace is 4C1*48C1
Number of ways in which both in the cards are Ace are 4C2.
Therefore the required probability is (4C2 + 4C1 x 48C1)/52C2.
Hope this helps
Related Questions
Know More about
Joint Entrance Examination (Main)
Application | Eligibility | Result | Preparation Tips | Question Paper | Admit Card | Answer Key | Accepting Colleges
Get Updates BrochureYour Joint Entrance Examination (Main) brochure has been successfully mailed to your registered email id “”.




