can I get any nit in obc category with CRL rank 2 lakh??????
Hello There ,
You can apply for josaa counselling ,according to your category you can get some lower nit's or your home state nit as the cutoff is low and also you can get a seat in csab . Apart from nit , you can apply for iiit and various gfti also , which offer admission through josaa and you can apply for state counselling for applying to the state government colleges .
For more details you can check this page -
https://engineering.careers360.com/articles/jee-main-cutoff-for-top-nits
https://engineering.careers360.com/articles/jee-main-cutoff-for-top-iiits
To know your admission chances in JOSSA counseling & State counseling, You can use JEE Main college Predictor tool here .
https://engineering.careers360.com/jee-main-college-predictor?icn=QnA&ici=qna_answ
As you are a general category student and have secured 200000 Crl rank in jee mains , then sorry you will not get any nits. As the competition level is increasing day by day and this statement applies mainly for general category students, so for getting a seat in nits from general category, your rank must be roughly under 30000.
Also there is no chance to get seat from your obc category. Because your obc rank is very far from the cutoff ranks required for getting seats in nits.
But if you belong from home state of certain low nits then with this much low rank you can get some lower nits via applying hone state quota like - nit sikkim, nit mizoram, nit meghalaya, etc.
Other wise there is no chance that you can get any nits of you are from other states.
So, you better try at some other state colleges like hbti kanpur or private institutions like kalinga institute of industrial technology or cv raman global university as many low rankers can easily get admission in these private colleges.
Also check out our jee mains college predictor tool to get an appropriate idea of colleges that you can get on basis of your jee mains rank :-
https://engineering.careers360.com/jee-main-college-predictor?icn=QnA&ici=qna_answer