when one mole of ice is converted to water at 0c and 1atm the work done (Latm) is
Hello,
Since heat is absorbed here at constant pressure so
deltaH=1440 calories.
deltaU can be calculated by using the formula :
deltaU = deltaH-PdeltaV
P=1 atm , deltaV = 0.0196l - 0.180L = 0.016L
PdeltaV=1*0.016L = 0.016Latm = 0.016 * 24.217 calories
so deltaU=1440cal-0.016 * 24.217 cal
So there is negligible work done
So you can write deltaH=deltaU.




