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work done in converting one gram of ice at -10degree C into stream at 100degree C is

Sukhdev Sharma 22nd Jan, 2020

Answer (1)

Anamika Tiwari 28th Jan, 2020

Dear Sukhdev,

As per you question, the solution is:

Q= mass* heat of fusion.

Heat of fussion= 333 J

So, Q= 1*333= 333J.

Also,

Q= mass* specific heat* temp.

For ice, Q= 1*2.09*10= 20.9J

For water, 1*4.186*100 = 418.5 J

According to equation,

Q= mass* heat of vaporisation (2260J/g)

Q= 1*2260=2260 J/g

Total= 2260+ 418.5+20.9+333= 3032.5 J

And 3032.5 = 3.0325 kg.

Hope you get your answer.

Thank you!

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