Colleges

MET 2024 Rank Holders

The candidate must have passed 10+2 or A Level or IB or American 12th grade or equivalent examination with Physics, Mathematics and English as Compulsory subjects, along with any one of Chemistry or Computer Science or Biotechnology or Biology or Statistics or Engineering Drawing as optional subject for admission to B Tech, with minimum of 50% marks in Physics, Mathematics and the optional subject, put together.

Direct admission

Direct admission is possible if seats are available after MET.

Candidates need to meet one of the following criteria:

• Candidates have a JEE rank and qualified for JEE Advanced in that year
• Based on candidate’s SAT score
• MET 2024 rank holders, who could not come for counseling.
• All Students with Physics, Mathematics and English as compulsory subjects and who have 60% or equivalent in PMX subjects in their 12th std. where X could be Chemistry, Computers Science, Biotechnology, Biology, Statistics or Engineering Drawing.

Regular Mode: 

• The applicant must be a citizen of India. (Candidates holding OCI status must have to apply under DASA mode.
• The applicant must be appearing in Paper 1 (B.E. /B.Tech.) during one or more sessions of JEE (Main) 2025 Examination conducted by the National Testing Agency (NTA).
• The applicant must have passed with an aggregate of minimum 60% marks or equivalent grade in Class 12th (10+2) examination. Applicants appearing in the class 12th examination are also eligible to apply.
• The applicant must have secured an aggregate of minimum 60% marks or equivalent grade in Mathematics, Physics and Chemistry in Class 12th examination.
• The applicant must have passed with an aggregate of minimum 60% marks or equivalent grade in Class 10th examination.

DASA Mode: 

• The applicant should have a valid minimum aggregate score of 1040 (out of a maximum of 1600) in SAT conducted by College Board, USA.

OR

• The applicant must have secured a minimum of 90 percentile as Final NTA score (percentile) in Paper 1 (B.E./B.Tech.) of JEE (Main) 2025 Examination conducted by the National Testing Agency (NTA).
• The applicant must have passed with an aggregate of minimum 60% marks or equivalent grade in Class 12th (10+2) examination or equivalent examination from the board recognised by Association of Indian Universities (AIU) with adequate proficiency in English. Applicants appearing in the class 12th examination are also eligible to apply.

• The applicant must have secured an aggregate of minimum 60% marks or equivalent grade in Mathematics, Physics and Chemistry in Class 12th examination.

• The applicant must have passed with an aggregate of minimum 60% marks or equivalent grade in Class 10th examination or equivalent from the board recognised by Association of Indian Universities (AIU).

Direct Mode - Only for Central and State Board Toppers:

• An applicant who is among
• Top 10 students in Class 12th examination in the academic year 2024-25 from the Merit List of the Rajasthan Board of Secondary Education (RBSE), provided that official Merit List mentioning such ranks is published.

OR

• Top 2 students in Class 12th examination in the academic year 2024-25 of all those Central and State recognized boards in India who publish authorized Merit List indicating ranks.
• The applicant must have passed with an aggregate of minimum 60% marks or equivalent grade in Class 12th (10+2) examination.
• The applicant must have secured an aggregate of minimum 60% marks or equivalent grade in Mathematics, Physics and Chemistry in Class 12th examination.
• The applicant must have passed with an aggregate of at least 60% marks or equivalent grade in Class 10th examination.