As an SC female candidate with a CRL rank of 254246 and SC rank of 14188, getting Electrical and Electronics Engineering (EEE) in top NITs might be difficult. However, you may have chances in newer or less competitive NITs like NIT Nagaland, NIT Mizoram, NIT Sikkim, NIT Arunachal Pradesh, or

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To be eligible for the JEE Advanced exam, you need to meet certain criteria, including minimum percentage requirements in your 12th-grade board exams. Check the official notification or website of the exam conducting authority for specific eligibility criteria for MP Board students.

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Correct Answer: Illness or injury

Solution : Illness or injury is an example of physiological stress, as it involves a physical response to a stressor that affects the body's functioning.

Correct Answer: Both assertion and reason are true, and the reason is the correct explanation of the assertion.
  

Solution : The correct answer is (a) Both assertion and reason are true, and the reason is the correct explanation of the assertion.

The assertion is true. Dematerialization indeed refers to the

Correct Answer: 40%

Solution : Given: A person bought some pens at the rate of 14 for a rupee and sold them at the rate of 10 for a rupee.
Profit percentage = $\frac{SP–CP}{CP}×100$, where SP is the selling price and CP is the cost price.
= $\frac{14–10}{10}\times 100$
=

Correct Answer: 6

Solution : The bottom face in the last cube is the face opposite to 4.
Taking dice positions 2 and 3 with 4 as the common face,

Moving clockwise from the common face with 4,

Pairs of opposite faces –

So, the bottom face in the last

Correct Answer: 4.2 and 4.4

Solution : Given: $\frac{\frac{1}{3}+[4 \frac{3}{4}–(3 \frac{1}{6}–2 \frac{1}{3})]}{(\frac{1}{5} \text { of } \frac{1}{5} \div \frac{1}{5}) \div(\frac{1}{5} \div \frac{1}{5} \times \frac{1}{5})}$
$=\frac{\frac{1}{3}+[ \frac{19}{4}–(\frac{19}{6}– \frac{7}{3})]}{(\frac{1}{25} \div \frac{1}{5}) \div(\frac{1}{5} \times 5 \times \frac{1}{5})}$
$=\frac{\frac{1}{3}+[ \frac{19}{4}–(\frac{19–7\times 2}{6})]}{(\frac{1}{25} \times 5) \div(\ \frac{1}{5})}$
$=\frac{\frac{1}{3}+[ \frac{19}{4}–\frac{19–14}{6}]}{\frac{1}{5} \div\ \frac{1}{5}}$
$=\frac{\frac{1}{3}+[ \frac{19}{4}–\frac{5}{6}]}{\frac{1}{5} \times 5}$
$=\frac{\frac{1}{3}+[

Hii There,

The Master of Science (M.Sc) in Mathematics is a two-year postgraduate program consisting of four semesters. This degree program is structured to provide students with an in-depth understanding of advanced mathematics, fostering critical reasoning, analytical thinking, and research skills. It encompasses a broad spectrum of subjects within M.Sc