Rank
Hello Dear Student, With an SRMJEEE Phase 2 rank of 12,962, securing CSE with specialization in Cyber Security at the SRM Kattankulathur (KTR) main campus is borderline and highly competitive. You can check, find and access more information here:
Hey there,
With a NEET 2026 score of 457, your expected All India Rank (AIR) is likely to be around 90,000–1,20,000. The exact rank will depend on factors such as the exam difficulty, number of candidates, and overall performance in NEET 2026. The official rank may vary from this estimate.
With a COMEDK rank of 720 and KKR (Kalyana Karnataka Region) reservation , you have a good chance of getting Computer Science & Engineering (CSE) at R.V. College of Engineering through COMEDK counselling.
Here's why:
In 2025 Round 1 , the KKR closing rank for CSE at RVCE was around
Hello Dear Student, With a CLAT AIR of 19,688, your chances of a seat in regular counseling rounds are slim. However, you have realistic prospects through vacancy/spot rounds or state quotas. Your best option is to target the Tamil Nadu National Law University (TNNLU Tiruchirappalli) using your state domicile and
Hello Student,
To get to know the college based on your KCET Rank, you can use our KCET college predictor tool given in the link below.
Predictor Link - KCET 2026 College Predictor
Hello Dear Student,
With a JEE Main CRL of around 3,00,000 and an EWS rank of around 46,000 , getting Computer Science and Engineering (CSE) at Odisha University of Technology and Research is highly unlikely .
Why?
With a WBJEE TFW rank of 23,389 , getting Computer Science and Engineering (CSE) in a government engineering college is generally difficult, as TFW cutoffs for CSE are usually much lower.
However, you have good chances of getting CSE or IT through the TFW quota in several
For the May 2026 session (conducted in July 2025, results released May 23, 2026), the Round 1 cutoff rank for the ST category is 31,313 .
January 2026 Session (Round 1 ST Cutoff): 27,569
May 2026 Session (Round 1 ST Cutoff): 31,313
You can get directly find,
You can get directly find, check, get more information here:
Hope it helps!
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