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How admission in Boptom course

mjaisinghani62 20th Jan, 2024

Hello Pankaj

B.Optom is bachelor of optometry .

For admission to this B .optometry course you will have to appear for entrance exam . Entrance exams are - TJEE , CUET ,KCET ,GUJCET ,GITAM GAT and IUET .

Eligibility criteria for the course is that you must have passed class

13 Views

what is duration of Normal MA postgraduate degree & LLM after 5 years BA.LLB integrated Degree?

Yash 16th Nov, 2024

The duration of the normal MA degree programme and LLM degree programme offered across various universities, institutes and colleges in India is generally two years after a candidate pursue the five-year, full-time BA LLB Integrated degree programme. However, there are some universities, institutes and colleges in India which offers an

54 Views

I am Student of class 12 with physics , chemistry , biology , english and physical education as main subjects. Math is my 6th (additional subject) . Now my question is can I give jee mains with math as 6th subject and can I also take admission in engineering college.

Ishita 20th Jul, 2024

Hello Aspirant

Admission into an Engineering college requires you to have Science (Physics, Chemistry, Math, Biology is not required) in your 11th and 12th grades. Seeing you had all these subjects in your school, you are eligible to appear for the JEE exam. You just make sure you scored 50%+

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Question : Sulphuric acid is

Option 1: monobasic

Option 2: dibasic

Option 3: tribasic

Option 4: tetrabasic

Team Careers360 17th Jan, 2024

Correct Answer: dibasic


Solution : The correct option is dibasic.

Sulphuric Acid is dibasic as it replaces two hydrogen atoms and has basicity 2. Its Chemical name is H2SO4. Oil of Vitriol and King of Chemical, are its other names, and its nature is Oily,

17 Views

Question : If $a^2+b^2+c^2=14$ and $a+b+c=6$, then the value of $(ab+bc+ca)$ is:

Option 1: 11

Option 2: 12

Option 3: 13

Option 4: 14

Team Careers360 23rd Jan, 2024

Correct Answer: 11


Solution : Given: $a^2+b^2+c^2=14$ and $a+b+c=6$.
On squaring the given equation $a+b+c=6$, we get,
$(a+b+c)^2=6^2$
⇒ $a^2+b^2+c^2+2(ab+bc+ca)=36$
Substitute the value of $a^2+b^2+c^2=14$ in the above equation and we get,
⇒ $14+2(ab+bc+ca)=36$
⇒ $2(ab+bc+ca)=22$
⇒ $(ab+bc+ca)=11$
Hence, the correct answer is 11.

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