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39 Views

As a SC Candidate, what is the NEET marks are needed for getting admission in CMC Vellore Collage

Sajal Trivedi 22nd Jan, 2024

Hello aspirant,

In the Undergraduate NEET test, all students were required to have "obtained a minimum of marks at 50th percentile" (40th percentile for those vying for seats in the SC/ST quota, subject to modifications in the minimum qualifying percentile declared by the Government).

For more information you can visit

16 Views

Sainik school question paper and answers download

Sajal Trivedi 23rd Jan, 2024

Hello aspirant,

The Sainik School admission question papers PDF for the Class 6 and 9 exams are released by the National Testing Agency, or NTA.

Students can better grasp the format and degree of difficulty of the All India Sainik School Entrance Exam by using AISSEE practice questions .

To

20 Views

Question : Directions: Which of the following letter clusters will replace the question mark (?) in the given series?
XG, UJ, RM, OP, ?

Option 1: MR

Option 2: LS

Option 3: MS

Option 4: LR

Team Careers360 25th Jan, 2024

Correct Answer: LS


Solution : Given:
XG, UJ, RM, OP, ?

In the above-given series, subtract 3 from the place value of the first letter and add 3 to the place value of the second letter.
XG→X – 3 = U; G + 3 = J
UJ→U – 3 =

47 Views

when can i join for admission at mass communication course

Shivanshu 24th Mar, 2024

Dear aspirant !!

Hope you are doing good !

For an undergraduate course, the candidates generally need to have successfully passed 10+2 education in any stream . After completing a Bachelor's degree, students will be eligible for a postgraduate degree in Mass Communication.

Visit here for more details:

https://www.careers360.com/courses-certifications/mass-communication-courses-brpg

Hope

30 Views

Question : The remainder when $19^{19}+20$ is divided by 18, is:

Option 1: 3

Option 2: 2

Option 3: 1

Option 4: 0

Team Careers360 24th Jan, 2024

Correct Answer: 3


Solution : To find: The remainder when $19^{19}+20$ is divided by 18.
Now, 19 $\equiv$ 1 (mod 18)
⇒ 1919 $\equiv$ 119 (mod 18)
⇒ 1919 $\equiv$ 1 (mod 18)
⇒ (1919 + 20) $\equiv$ (1 + 20) (mod 18)
⇒ (1919

9 Views

Iam in second year BA can I take admission for llb 5 years without canceling BA

Satakshi 24th Feb, 2024

It is only possible if u are pursuing ba though distance as while pursuing dual course one should be full time and other through distance learning. And if in 2 nd year and what to go in law u can  complete Ba and then go for LLB

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