Dear Aspirant,

For admission in B.Com Hons from Calcutta University mathematics is not the compulsory subject

The eligibility is 10+2 with minimum 50 % passing percentage but atleast have some any of the subject like Business economics, Financial Accountancy, Cost accounting, Book keeping, Business Mathematics, Secretarial practice,etc

Hope this helps

Hi there,

If you are in 11th and you are preparing neet then I think you must be having pcb as your subject and 2 optional subject.

Hence Maths is nowhere, but if you have chosen maths as your optional subject that is pcmb then you must have to score

Hello student yes you can start preparing for Neet entrance examination, Prefer NCERT to build your basic concept and make sure you do each and every example and exercise questions of Ncert before jumping to a reference book.

You can also subscribe to careers360 knockout package for preparing and qualifying

Hello Tanu!
If you'll be in Class 11th this year then it's the right time to start your NEET-UG preparation.
You will have sufficient time in your hand. Most of the aspirants start preparing from this level only. Just be sure to make proper utilization of the 2 years (approx.)

Hello aspirant,

Class 11th and Class 9th exams results are declared autonomously by schools. Every school has their own academic calendar and result declaration date. But since due to covid-19 the schools are shut, therefore there's a delay in declaration of the result. You can expect the declaration of your

Hello student I'm sorry to inform you but ETOOS is a third party portal and we can't help you with third party products i request you to please help me with the entrance examination you're preparing about so that I can provide you best available packages.

Feel free to comment

oh boi icse students have that in class 10th half yearly. Its damn easy

Hello student,

Government of Madhya Pradesh offers a separate scholarships for both boys and girls of SC ,ST, OBC . You can apply it only in post matric level of class 11 and 12.

There is a separate MP scholarship portal which provides students all scholarships information. here is the

Hey!

Solution is given below :

Since there are four metal atoms in one unit cell, the unit cell is fcc type. For fcc unit cell, radius r=0.3535 a, where a is the edge length of the unit cell. Hence, r=0.3535×361 pm =127.6 pm

Thus, the radius of one atom