entrance exam
Hello,
Some of the common entrance exams for B.Tech admissions in Hyderabad include:
1 TS EAMCET
2 JEE Main
3 BITSAT
4 VITEEE
These are some of the examinations one can give to get admission in B Tech in Hyderabad and also some colleges does not have any specific exam.
Hello
For B.Ed entrance exam prep, here are following things you can do-
1 Use guidebooks tailored to your exam.
2 Review previous years' papers.
3 Study general knowledge and current affairs.
4 Brush up on teaching aptitude and educational psychology.
5 Utilize online resources for practice tests and materials.
Question : Directions: Which one set of letters when sequentially placed at the gaps in the given letter series shall complete it? c_bba_cab_ac_ab_ac
Option 1: babcc
Option 2: bcacb
Option 3: acbcb
Option 4: abcbc
Correct Answer: acbcb
Solution : Given: c_bba_cab_ac_ab_ac
To fill the series we have to divide the series – c_b/ba_/cab/_ac/_ab/_ac Let's check each option: First option: babcc; cbb/baa/cab/bac/cab/cac; (No pattern has been found.) Second option: bcacb; cbb/bac/cab/
Question : If $x+y+z=1, \frac{1}{x}+\frac{1}{y}+\frac{1}{z}=1,$ and $xyz=-1$, then $x^3+y^3+z^3 $ is equal to:
Option 1: –1
Option 2: 1
Option 3: –2
Option 4: 2
Correct Answer: 1
Solution : Given: $x+y+z=1,\frac{1}{x}+\frac{1}{y}+\frac{1}{z}=1$, $xyz=-1$ Consider, $\frac{1}{x}+\frac{1}{y}+\frac{1}{z}=1$ ⇒ $xy+yz+zx=xyz=-1$ Now, $x+y+z=1$ ⇒ $(x+y+z)^2=1^2$ ⇒ $x^2+y^2+z^2+2(xy+yz+zx)=1$ ⇒ $x^2+y^2+z^2+2(-1)=1$ ⇒ $x^2+y^2+z^2=3$ We know, $x^3+y^3+z^3-3xyz=(x+y+z)(x^2+y^2+z^2-(xy+yz+zx)$ So, putting all the values, we get, ⇒ $x^3+y^3+z^3-3×(-1)=1×[3-(-1)]$ ⇒ $x^3+y^3+z^3=4-3$ $\therefore x^3+y^3+z^3=1$ Hence, the correct answer is 1.
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