Hi

hope you doing well

Yes, you can appear for both Paper 1 (B.Tech) and Paper 2 (B.Arch or B.Planning, each serving a distinct purpose. You can choose to appear for either one or both, depending on your course preferences.

Paper 1:

• Purpose: For admission to B.E./B.Tech programs in NITs, IIITs, CFTIs, and other engineering colleges.
• Subjects: Physics, Chemistry, and Mathematics.
• Mode: Computer-based test (CBT).

Paper 2:

This paper is further divided into two parts :

• Paper 2A – For B.Arch (Bachelor of Architecture).
• Paper 2B – For B.Planning (Bachelor of Planning).

Each paper requires a separate registration during the application process. Since if you are aiming for a change from B.Planning to B.Tech or vice versa, it’s important to confirm if both were registered during your application.

hope you get it and find this info suitable

Best Wishes.

Hello student,

If you've forgotten your application number, you can try the following:

1. Check it on your previous emails (confirmation email NTA sends when you'd first registered)

2. Check it on your admit card

3. On the NTA portal, there's a tab "forgot application number". Click on that, and you'll be asked to enter your credentials and do a short verification, before you get it via email

If you need information regarding which colleges you would be eligible for based on your marks and details, then you can refer to the Careers360 JEE Main College Predictor: https://engineering.careers360.com/jee-main-college-predictor?

Correct Answer: Rs 100

Solution : Answer = Rs 100

Bank A/c Dr.                                              98

To Deb. Application and allotment A/c                      98
 

Deb. Application and allotment A/c Dr       98

Loss on the issue of Deb. A/c Dr                 7

To % Deb. A/c                                                         100

To Premium on Red. of Deb. A/c                                5

Hence, the correct option is 3.

Correct Answer: 40

Solution : Dimensions of cuboid are 20, 16 and 8 cm.
The length of the side of the cube = 4
Volume of cuboid = $l\times b\times h$
Volume of cube = $a^3$
Number of cubes = $\frac{\text{Volume of cuboid}}{\text{Volume of cube}}$
= $\frac{20\times 16\times 8}{4\times4\times4}$
= 40
Hence, the correct answer is 40.

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