Correct Answer: of

Solution : The correct choice is the third option.

The preposition "of" is commonly used to indicate possession or association. In this context, it is used to convey that Atlas was a Titan characterized by enormous strength.

Therefore, the complete sentence would be: "In these mythologies, Atlas

Correct Answer: HQFZUMFRT

Solution : Given:
GOODNESS is coded as HNPCODTR

Here, alternate letters are increased by 1 position in the English alphabet. and the other alternate letters are decreased by 1 position.
Like, GOODNESS is coded as HNPCODTR –
G + 1 = H; O – 1 = N;

Correct Answer: Setting performance standard
 

Solution : Setting performance standard is the first step in the controlling process.
Hence Option A is correct.

Correct Answer: 24 cm

Solution : Area of the parallelogram = $28 \times 12 = 336\ \mathrm{cm^2}$
Let the length of the altitude of the triangle be $h$ cm.
​According to the question,
$\frac{1}{2}\times h \times 28 = 336$
⇒ $h = 12\times2$
⇒ $h = 24\text{ cm}$
Hence, the

Yes as per the Information Bulletin by NTA. Senior Secondary School Examination conducted by the National Institute of Open Schooling with a minimum of five subjects. will be eligible to write an exam for JEE Mains.

But to sit for JEE Advanced exam, only top 2.5 lakhs students will get

Correct Answer: 1862

Solution : The correct answer is 1862.

It was formally known as the High Court of Judicature at Fort William. The first high court in India was established in Calcutta (now Kolkata) in the year 1862 during British rule. After the Sepoy Mutiny in 1857, the

Correct Answer: Nile

Solution : The correct answer is Nile.

Nile is the longest river in the world. It is formed by the confluence of the river Blue Nile and White Nile. It originates from Burundi in Africa and drains into Mediterranean Sea. It has a length of about 6656

Yes on Careers360 portal You can our latest article for the same.

Correct Answer: $\frac{15}{8}$

Solution : Given: $\sec A=\frac{17}{15}$
$⇒\cos A = \frac{15}{17}$
$⇒\sin A = \sqrt{1-\cos^2 A}= \sqrt{1-(\frac{15}{17})^2}$ = $\sqrt{\frac{64}{289}}$ = $\frac{8}{17}$
$\therefore \cot A = \frac{\cos A}{\sin A} = \frac{\frac{15}{17}}{\frac{8}{17}} = \frac{15}{8}$
Hence, the correct answer is $\frac{15}{8}$.