Applying for PGCET with missing study certificates can be challenging but not impossible.

• Required Certificates: While specific requirements vary, generally, most study certificates (especially recent ones) are crucial.
• Missing Certificates: For missing certificates, you might need to obtain duplicate copies from respective schools. There might be specific procedures and fees involved.
• Non-Karnataka Board: Certificates from boards other than Karnataka might require specific conversions or equivalency certificates. Check PGCET guidelines for details.

Crucially, contact the PGCET helpline or visit the official website for precise information. They can guide you on specific requirements, alternatives, and potential solutions for your situation.

It's advisable to start the process early to avoid last-minute hurdles.

Hello aspirant,

The Karnataka PGCET 2024 application form will be made available on the official website by KEA. The PGCET application form can be completed online at kea.kar.nic.in by candidates. On the official website, the authorities will declare the Karnataka PGCET 2024 registration date. Prior to submitting their application, candidates were required to review the qualifying requirements for the Karnataka PGCET. There are several steps involved in the Karnataka PGCET application procedure, including filling out the form, uploading papers, paying the application cost, and submitting it.

For more information you can visit our website by clicking on the link given below.

https://engineering.careers360.com/articles/karnataka-pgcet-application-form

Thank you

Hope this information helps you.

Correct Answer: Web browser

Solution : The correct answer is a Web browser.

The tool used to view pages and navigate the World Wide Web is a web browser. A web browser is a software application that allows users to access, retrieve, and view information on the internet. It interprets HTML (Hypertext Markup Language) documents, and displays them as web pages, enabling users to interact with various online content.

Correct Answer: 4.2 and 4.4

Solution : Given: $\frac{\frac{1}{3}+[4 \frac{3}{4}–(3 \frac{1}{6}–2 \frac{1}{3})]}{(\frac{1}{5} \text { of } \frac{1}{5} \div \frac{1}{5}) \div(\frac{1}{5} \div \frac{1}{5} \times \frac{1}{5})}$
$=\frac{\frac{1}{3}+[ \frac{19}{4}–(\frac{19}{6}– \frac{7}{3})]}{(\frac{1}{25} \div \frac{1}{5}) \div(\frac{1}{5} \times 5 \times \frac{1}{5})}$
$=\frac{\frac{1}{3}+[ \frac{19}{4}–(\frac{19–7\times 2}{6})]}{(\frac{1}{25} \times 5) \div(\ \frac{1}{5})}$
$=\frac{\frac{1}{3}+[ \frac{19}{4}–\frac{19–14}{6}]}{\frac{1}{5} \div\ \frac{1}{5}}$
$=\frac{\frac{1}{3}+[ \frac{19}{4}–\frac{5}{6}]}{\frac{1}{5} \times 5}$
$=\frac{\frac{1}{3}+[ \frac{57–10}{12}]}{1}$
$=\frac{1}{3}+\frac{47}{12}$
$=\frac{4+47}{12}$
$=\frac{51}{12}$
$=4.25$
Hence, the correct answer is 4.2 and 4.4.