Hello,

Yes,You are qualified to take the NIMCET.

The following degrees, including mathematics or statistics as one of the topics, are the minimum requirements for the NIMCET: B.Sc., B.Sc. (Hons. ), BCA, or BIT with a minimum of three years of full-time study from an accredited university.

Additionally eligible for the NIMCET are applicants from the open university.

You are qualified for the NIMCET since math was a requirement for graduation.

Passin 10+2 without math is not a factor. You are eligible.

Good Luck!!

You can download Maths Syllabus 2022-23 pdf for UP board from below link:

https://school.careers360.com/boards/upmsp/up-board-class-10-syllabus

Best of Luck!

Hello Aspirant

Since math is your extra subject, you will still be considered to have passed if you pass the other 5 courses but fail in math.  You need to pass in 5 subjects to be promoted to higher level.

However, Failing in more than one subject implies you've flunked in class 11. So you'll definitely have to repeat class 11 .

I hope this answers your question.

Thanks

Hello!

The B.Tech course duration is between three to four years, depending on the country and the institution. In India, the duration to complete the degree is four years, spread over eight semesters. The course duration is same for everyone unless someone has done diploma in relevant subject.

Since you have completed your class 12 and currently pursuing BA, it will take 4 years for you to complete B.Tech.

Hope this answers your query!

Hi

With   97 percentile

---------------------) Your obc rank will be roughly around  8k

Now,

Making  prediction is difficult as  cutoff  depends upon various factors like :-

-----------) number of students/ candidates  that appeared in the  jee main exam,

-----------) number of available seats,

-----------) jee main examination difficulty level.

-----------) the branch you want,

-----------) the category you belong etc.

-----------) your rank in jee main

But yes,

When we go through previous year trend then

>>>>>>>>> For your  rank

You have chances in following  which are listed below along with their closing rank in 6th round of josaa counselling 2020 under other state/ all india quota   :-

----------) National Institute of Technology, Manipur:- computer science:-8349 obc rank

-----------) National Institute of Technology, Warangal:-Metallurgical and Materials Engineering :-8409 obc rank

----------) NIT Mizoram :- cse :- 9343 obc rank

-----------) National Institute of Technology Nagaland:- computer science:-9632 obc rank

-----------) National Institute of Technology, Uttarakhand:- Mechanical Engineering :-10001 obc rank

And a few more

No, you want face any problem in getting  admission in NIT is even if you get 0 percentile in JEE main but your over all percentile is 97% time this is because there is no sectional cut off in JEE main to be eligible for nits, actually there is no qualifying cut off to be eligible for NITs your admission is completely on the basis of rank in JEE main , qualifying cut off is only for JEE advanced but for that to there is no sectional cut off

You can check the closing ranks  at official website of josaa by going through the link given below

https://josaa.nic.in/Counseling/seatallotmentresult/currentorcr.aspx

Or

For previous year cut offs of top colleges like NITs, IIITs , you can also refer our page at :-

NITs :- https://engineering.careers360.com/articles/nits-cutoff-for-top-btech-branches

IIITs:- https://engineering.careers360.com/articles/jee-main-cutoff-for-top-iiits

Above prediction has been made  considering  past year cut off data but  closing rank for colleges varies every year depending upon many factors like jee main question paper difficulty, number of students writing the exam etc so

To have a personalised report on your chances of getting a college you can go through our college predictor, it will give you complete list of colleges which you can get on the basis of the category you belong to,  your home state, your gender etc, the link for  jee main college predictor is provided below

https://engineering.careers360.com/jee-main-college-predictor?icn=QnA&ici=qna_answer

To help you  further,

To give an idea of jee main 2022 qualifying cut off

Minimum percentile in jee main 2021 to qualify it to be eligible for jee advanced is given below :-

--------) general :-87.8992241 percentile

--------) EWS:- 66.2214845 percentile

--------) OBC-NCL :- 68.0234447 percentile

--------) SC :- 46.8825338 percentile

--------) ST:- 34.6728999 percentile

--------) PWD :- 0.0096375 percentile

You can check the same at our page the link is provided below

https://engineering.careers360.com/articles/jee-main-cutoff

Regards

ADITYA KUMAR

Hello Aspirant,

See it is quite difficult to tell you an exact figure of your percentile and rank because it keeps on changing every year depending upon various factors but yes we can help you with approximate figures on the basis of analysis of previous year's data.

So If we go through the analysis of marks Vs Percentile Vs rank for JEE-Main 2021 then according to the marks mentioned by you in the question your percentile and CRL rank are expected to be in the range of 96.0687115-96.93721175 and 43174-33636  respectively .

Note that the percentile and rank which are predicted is only the expected percentile and rank on the basis of previous year's data so your actual percentile  and rank might vary depending upon current factors.

To have a list of all those colleges which you can get based upon your JEE-Main ranks or score you can use JEE-Main College Predictor:-

https://engineering.careers360.com/jee-main-college-predictor?icn=QnA&ici=qna_answer

Or

You can also check out our Engineering Counselling Subscription package in which you get B.Tech companion tool which will guide you in all your counselling and admission related issues and along with this you will be getting 3 one-to-one counselling sessions by our experts :-

https://www.careers360.com/campaign/Engineering-Counseling-Subscription

I hope this information helps you.

Good Luck!!

Dear aspirant hope you are doing well..

yes, you are eligible for MCA. As Few college don't required maths as compulsory subjects for MCA. Like Crist university.

MCA Eligibility Criteria

Candidates should have completed their BCA/ B.Sc / B.Com or a similar stream and should have scored at least 50% marks in the Undergraduate level. Mathematics should be a compulsory subject in the 10+2 grade in order to be eligible

for more details click on the link below

https://www.careers360.com/courses/mca-master-of-computer-applications

Hope it's helpful thank you

Hi ,

If you have RT in one subject that means you have to repeat theory of that subject. CBSE provides an opportunity for those students who have got RT in subject for writing compartment exam in one subject. Since you have rt  in maths, you have to write compartment exam and pass in that subject.

The eligibility criteria for BSC information technology is Candidates who have completed 10+2 from a recognized council or university . Candidates with Physics, Chemistry, and Mathematics as compulsory subjects in 10+2 are eligible to apply. Some colleges prefer candidates with Computer Science/ Statistics as compulsory subjects. Since the eligibility criteria says that candidates should have passed their 12th, you have to pass in mathematics. Also mathematics is one of the compulsory subjects mentioned above. After making your status in maths subject as passed you can apply for BSC information technology.

Thank you.

Hello!

Yes, you can pursue food technology course without maths. The eligibility criteria for getting admission in the course is that t he candidate must have their 10+2 with Physics , Chemistry , and Maths or Physics, Chemistry, and Biology as main subjects from recognized board and they must have secured 55% marks.

Hope this helps.