Correct Answer: GB 23

Solution : Given:
EZ 10, ?, ID 36, KF 49, MH 62

Add 2 in the positional value of each letter and add 13 to each number of the previous term to get the next term –
EZ 10→E + 2 = G; Z + 2

Correct Answer: Only conclusion I follows

Solution : The possible Venn diagram according to the given statement is as follows –

Let's analyse the conclusions –
Conclusion I: Rachel is not a horse – From the Venn diagram, it is evident that Rachel is a girl and no girl is

Correct Answer: B.G. Tilak

Solution : Correct Answer is B.G. Tilak

Bal Gangadhar Tilak, often known as Lokmanya, was India's most notable liberation warrior. He founded two newspapers, one in Marathi called 'Kesari' and another in English called 'Maratha' .Kesari's first editor was G.G. Agarkar.
From the first day of

Correct Answer: very richer than jim

Solution : The first option is correct.

In the sentence provided, the error lies in the use of very with the comparative form of the adjective "rich". When making comparisons, adjectives like rich form their comparative and superlative degrees without the use of very

Correct Answer: Pune

Solution : The correct option is Pune.

The PARAM supercomputer in India is located in Pune, Maharashtra. The Centre for Development of Advanced Computing (C-DAC) in Pune planned and built it. PARAM supercomputers are used for a variety of applications by both public and commercial operators, including

Correct Answer: $\cos \left(\frac{\pi}{3}+x\right)$

Solution : Given, $\frac{\cos x-\sqrt{3} \sin x}{2}$
= $\frac{1}{2} \cos x-\frac{\sqrt3}{2}\sin x$
= $\cos x \cos \frac{\pi}{3} - \sin \frac{\pi}{3} \sin x$ [$\because\cos \frac{\pi}{3}=\frac{1}{2}$ and $\sin \frac{\pi}{3}=\frac{\sqrt3}{2}$]
= $\cos( \frac{\pi}{3}+x)$
Hence, the correct answer is $\cos( \frac{\pi}{3}+x)$.

Which board and how many grace marks did u got? If you're aggregate pcb is more than 50% then you're eligible don't worry about the grace mark that is given my every board in India except cbse and it is acceptable, reappearing 12th again will make you a private candidate,NMC

Hello Rajib

You can appear for neet if you have passed in chemistry subject.

Also it is important that you must get minimum 50%  aggregate marks in physics,  chemistry and biology. This means your total marks in physics ,chemistry and biology should be 150 ( minimum) .

Now your marksheet