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if am taking CA, which are the subjects involved in that and now i am 2 puc for degree which course should i take ,and some good college in less fees

ishratsadaf8 1st Feb, 2024

Greetings!

So, CA is the toughest course in India. After your PU you can take addmission in B.Com, BBM or BBA. For the colleges you can take admission in government colleges or m.sc College of Bangalore or government first grade college of davangere.

For CA there will be three levels

17 Views

can i join Diploma in medical laboratory after finishing my puc in commerce stream

mjaisinghani62 8th Feb, 2024

Hello Waziha

You can do D.M.L.T Course after completing PUC .

DMLT is Diploma in laboratory technology . It is two years Course including internship .

Eligibility for the Course is to have passed class xii or equivalent  course with  minimum 50% marks from any recognized university.

Course fees ranges

31 Views

Question : Directions: Four pairs of numbers have been given, out of which three are alike in some manner, while one is different. Choose out the odd one.

Option 1: 236 : 325 : 263

Option 2: 189 : 198 : 819

Option 3: 761 : 617 : 176

Option 4: 416 : 641 : 461

Team Careers360 15th Jan, 2024

Correct Answer: 236 : 325 : 263


Solution : Let's check each option –
First option: 236: 325 : 263; In the second number digits are different from the the first and the second number.
Second option: 189: 198 : 819; In all three numbers same digits are repeated.
Third

390 Views

What is my 12th/ PUC student/Reg number that i need to enter in the KCET application form 2024 ?

Tanya Gupta 18th Jan, 2024

Hello,


The 13 digit 'Student Number' issued from PUE Department has to be entered by the candidates who appeared for the 12th PUC exam.

To find your 12th/PUC student/Reg number for the KCET application form in 2024, you'll need to check your 12th/PUC registration documents or reach out to your

11 Views

Question : If $a^2+b^2+c^2=16$, $x^2+y^2+z^2=25$ and $ax+by+cz=20$, then the value of $\frac{a+b+c}{x+y+z}$ is:

Option 1: $\frac{3}{5}$

Option 2: $\frac{5}{3}$

Option 3: $\frac{4}{5}$

Option 4: $\frac{5}{4}$

Team Careers360 21st Jan, 2024

Correct Answer: $\frac{4}{5}$


Solution : Given: $a^2+b^2+c^2=16$----(equation 1)
$x^2+y^2+z^2=25$-----(equation 2)
$ax+by+cz=20$-----(equation 3)
Substitute the values of $b=0$ and $c=0$ in the given equation 1, we get,
$a^2+0^2+0^2=16$
$⇒a^2=16$
$\therefore a=4$
Substitute the values of $y=0$ and $z=0$ in the given equation 2, we get,
$x^2+0^2+0^2=25$
$⇒x^2=25$
$\therefore x=5$
Substitute the

23 Views

Question : The highest population density in India, according to the 2011 Census, is in ______________.

Option 1: Bihar

Option 2: Union Territory of Chandigarh

Option 3: National Capital Territory of Delhi

Option 4: Madhya Pradesh

Team Careers360 25th Jan, 2024

Correct Answer: National Capital Territory of Delhi


Solution : The correct option is the National Capital Territory of Delhi.

As of the 2011 Census of India, the National Capital Territory of Delhi had the highest population density among all states and union territories in India. Delhi is a densely

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