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Staff Selection Commission Combined Graduate Level Exam

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Question : The volume of a cone whose radius of a base and height are $r$ cm and $h$ cm respectively, is 400 cm3. What will be the volume of a cone whose radius of base and height are $2r$ cm and $h$ cm respectively?

Option 1: 100 cm3

Option 2: 1600 cm3

Option 3: 1200 cm3

Option 4: 800 cm3

Team Careers360 11th Jan, 2024

Correct Answer: 1600 cm3


Solution : Given: The volume of a cone whose radius of a base and height are $r$ cm and $h$ cm respectively, is 400 cm3.
The volume of a cone whose radius of base and height are $r$ cm and $h$ cm respectively

15 Views

Question : If $\tan (\alpha+\beta)=a, \tan (\alpha-\beta)=b$, then the value of $\tan 2 \alpha$ is:

Option 1: $\frac{a+b}{1-a b}$

Option 2: $\frac{a+b}{1+a b}$

Option 3: $\frac{a-b}{1+a b}$

Option 4: $\frac{a-b}{1-a b}$

Team Careers360 14th Jan, 2024

Correct Answer: $\frac{a+b}{1-a b}$


Solution : Given, $\tan (\alpha+\beta)=a$ and $\tan (\alpha-\beta)=b$
$\tan{2\alpha}=\tan((\alpha + \beta)+(\alpha - \beta)) = \frac{\tan(\alpha+\beta) + \tan(\alpha - \beta)}{1-\tan(\alpha + \beta)\tan(\alpha - \beta)}= \frac{a+b}{1-ab}$
Hence, the correct answer is $\frac{a+b}{1-ab}$.

11 Views

Question : Which of the following are warm - blooded animals?

Option 1: Whales

Option 2: Sharks

Option 3: Alytes

Option 4: Draco

Team Careers360 25th Jan, 2024

Correct Answer: Whales


Solution : The correct option is - Whales

Whales are warm-blooded, which means they are able to regulate their internal body temperature independent of the external environment. This is in contrast to cold-blooded animals, like reptiles, whose body temperature is determined by the surrounding environment. Warm-blooded animals,

18 Views

Question : Direction: If alphabets are serially numbered, one of the answers given below has a meaningful word hidden in it. Identify the answer.

 

Option 1: 5, 18, 5, 8, 1, 3, 5

 

Option 2: 20, 5, 1, 3, 8, 5, 18

 

Option 3: 5, 1, 3, 5, 20, 8, 18

 

Option 4: 18, 5, 3, 8, 1, 5, 20

 

Team Careers360 10th Jan, 2024

Correct Answer: 20, 5, 1, 3, 8, 5, 18

 


Solution : When alphabets are serially numbered →

ALPHABETS  A  B  C  D  E  F  G  H  I  J  K  L  M  N  O  P  Q  R  S  T  U  V  W  X  Y  Z
PLACE VALUE 1 2 3 4
130 Views

Question : Select the most appropriate option that can substitute the underlined segment in the given sentence. If there is no need to substitute it, select 'No substitution'.

The company decided to sell their stake in their subsidiary, because it was under massive debts.

Option 1: sell their stake in its subsidiary

Option 2: No substitution

Option 3: sell its stake in their subsidiary

Option 4: sell its stake in its subsidiary

Team Careers360 20th Jan, 2024

Correct Answer: sell its stake in its subsidiary


Solution : The correct choice is the fourth option.

The correct possessive pronoun should be used in accordance with the singularity or plurality of the subject. This change maintains consistency in possessive pronouns by using its to refer to the company and

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Question : Directions: Select the option that is related to the fifth number in the same way as the second number is related to the first number and the fourth number is related to the third number.
19 : 324 :: 25 : 576 :: 9 : ?

Option 1: 16

Option 2: 64

Option 3: 88

Option 4: 72

Team Careers360 19th Jan, 2024

Correct Answer: 64


Solution : Given:
19 : 324 :: 25 : 576 :: 9 : ?

In the given number pairs, subtract 1 from the first number and then find the square of the resultant, to get the second number.
Like, 19 : 324→(19 – 1)2 = (18)

29 Views

Question : The value of $\frac{(2.53)^3+(2.47)^3}{25.3 \times 25.3-624.91+24.7 \times 24.7}$ is 5 × 10k, where the value of k is:

Option 1: –2

Option 2: –1

Option 3: 1

Option 4: 2

Team Careers360 20th Jan, 2024

Correct Answer: –2


Solution : $\frac{(2.53)^3+(2.47)^3}{25.3 \times 25.3-624.91+24.7 \times 24.7}$
$\Rightarrow \frac{(2.53)^3+(2.47)^3}{25.3 \times 25.3-624.91+24.7 \times 24.7} = 5\times 10^{k}$
$\Rightarrow \frac{(2.53+2.47)(2.53^{2}+2.47^{2}-2.53\times 2.47)}{100\times2.53 \times 2.53-100\times6.2491+100\times2.47 \times 2.47} = 5\times 10^{k}$
$\Rightarrow \frac{(2.53+2.47)(2.53^{2}-6.2491+2.47^{2})}{10^{2}(2.53 \times 2.53-6.2491+2.47 \times 2.47)} = 5\times 10^{k}$
$\Rightarrow (2.53+2.47)\times10^{-2}=5\times 10^{k}$
$\Rightarrow 5\times10^{-2}=5\times 10^{k}$
$\therefore k=-2$
Hence, the correct answer

66 Views

Question : Vikas covered a certain distance by bike. If he covers 40% of the distance at 40 km/hr, 50% of the distance at 25 km/hr and the remaining 10% distance at 10 km/hr. Find his average speed over the whole distance.

Option 1: 25 km/hr

Option 2: 28 km/hr

Option 3: 26 km/hr

Option 4: 30 km/hr

Team Careers360 12th Jan, 2024

Correct Answer: 25 km/hr


Solution : Given, Vikas covers 40% of the distance at 40 km/hr, 50% of the distance at 25 km/hr, and the remaining 10% distance at 10 km/hr.
Let the total distance be $100x$
We know the average speed
= $\frac{\text{Total distance}}{\text{Sum of total speed}}$
= $\frac{100x}{\frac{100x\times40\%}{40}+\frac{100x\times50\%}{25}+\frac{100x\times10\%}{10}}$

11 Views

Question : Who was the first Chancellor of Jamia Millia Islamia University at Aligarh?

Option 1: Abdul Ghaffar Khan

Option 2: Rajkumari Amrit Kaur

Option 3: Hakim Ajmal Khan

Option 4: Sir Syed Ahmad Khan

Team Careers360 14th Jan, 2024

Correct Answer: Hakim Ajmal Khan


Solution : The correct answer is Hakim Ajmal Khan.

Hakim Ajmal Khan, who was born in 1868, founded the renowned Jamia Millia Islamia in Delhi as well as his own Tibbiya, or Medical College. Ajmal Khan, also known as Hakim Ajmal Khan, was a

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