Staff Selection Commission Combined Graduate Level Exam
Question : Comprehension: Read the following passage and answer the questions given after it. Quarantine and self-isolation need not be monotonous and stifling. They can be the gateway to work, be it in the arts or the sciences, that define the history of the world. Isaac Newton, Charles Darwin, John Milton and Lord Byron used much time to add to their formidable body of work in science and literature. It was not called lockdown in their time, but they spent long spells in isolation when medicine was not as developed as it is now. The University of Cambridge, where all four were studied, delved into its archives to collate their activities during such periods of isolation centuries ago. Isaac Newton (Trinity College): Considered Trinity’s most accomplished alumni, he exemplified productivity during a pandemic. Like many in Cambridge during the Great Plague of 1655-56, he retreated to the countryside to escape the disease-ridden city and spent two extended periods at his family home in rural Lincolnshire. Newton thrived in isolation, and later described it as one of the most productive times in his life, finding the space to reflect on and develop his theories on optics, calculus, and the law of motion and gravity. It was during this time that he conducted his famous prism experiment. “He bored a hole through his window shutters to produce a single, thin beam of light to pass through two prisms, proving for the first time that prisms did not create colours, but merely separated colours that were already there,” the university’s researcher, Alisha Matthewson-Grand, wrote. “Indeed, Newton was so intellectually transformed by his period of isolation that later commentators have referred to his time away from Cambridge as his annus mirabilis, or his year of wonders.” Charles Darwin (Christ’s College): Darwin’s experience with isolation was not the result of a pandemic but his own chronic ill health. He suffered from a myriad of unexplained symptoms, including vertigo, vomiting, cramps, fatigue, anxiety and visual disturbances. He noted in his autobiography of 1876 that “few persons can have lived a more retired life than we [Darwin and his wife Emma] have done. Besides short visits to the houses of relations, and occasionally to the seaside or elsewhere, we have gone nowhere.” Darwin believed that periods of isolation and ill health helped his career. At home, he was free from the demands placed on other scientists (teaching, administrative work), and thus able to devote himself entirely to research; he wrote: “Ill-health, though it has annihilated several years of my life, has saved me from the distractions of society and amusement.” Lord Byron (Trinity College): In 1811, Lord Byron was forced to quarantine in Malta after returning from a cholera-ravaged Greece. He was furious at the prospect of spending 40 days in lockdown, a measure he considered to be draconian and unnecessary. While confined, he wrote ‘Farewell to Malta’, a satirical poem attacking the island for (among other things) “Its smoky towns and cloudy sky” and its “cursed street of stairs”. He references his quarantine explicitly in the first verse “Adieu, thou damnedest quarantine / That gave me fever, and the spleen!’. John Milton (Christ’s College): The author of ‘Paradise Lost’ spent some time away from Cambridge as a first-year undergraduate in 1626, when the town was hit by bubonic plague. He was home in London when he wrote Elegia Prima, his first Latin elegy. The work is an early example of his aptitude for verse composition, as well as his impressive flair for comedy. Question: After reading this passage it can be said that it is:
Option 1: a newspaper article
Option 2: an encyclopaedic entry
Option 3: a news report
Option 4: a short story
Correct Answer: a newspaper article
Solution : The first option is correct.
Question : If $\frac{a}{b}+\frac{b}{a}=1$, then the value of $a^{3}+b^{3}$ will be:
Option 1: 1
Option 2: 0
Option 3: –1
Option 4: 2
Correct Answer: 0
Solution : Given: $\frac{a}{b}+\frac{b}{a}=1$ ⇒ $\frac{a^2 +b^2}{ab}=1$ ⇒ ${(a^2 +b^2)}={ab}$__________(equation 1) Now, $a^{3}+b^{3}={(a+b)(a^2+b^2–ab)}$ Putting the value of ${a^2+b^2}$ from equation 1, we get: ${(a+b)(a^2+b^2–ab)}$ = ${(a+b)(ab–ab)}$ = ${(a+b)×0}=0$ Thus, $a^{3}+b^{3}=0$ Hence, the correct answer is $0$.
Question : The sentences of a paragraph are given below in jumbled order. Arrange the sentences in the correct order to form a meaningful and coherent paragraph.
A. A certain aim will infuse one’s life with new meaning. B. At some point, an aimless person’s goals can be shattered and remain unfulfilled. C. In life, it is critical to have a workable objective or goal. D. A man who is aimless will never achieve success in life.
Option 1: DCAB
Option 2: BCDA
Option 3: ADCB
Option 4: DBCA
Correct Answer: ADCB
Solution : The third option is the correct choice: ADCB.
Explanation:
Question : Which ecologist is famous for studying plant life in the Indiana Dunes in 1896?
Option 1: Robert MacArthur
Option 2: G. Evelyn Hutchinson
Option 3: Henry Chandler Cowles
Option 4: Aldo Leopold
Correct Answer: Henry Chandler Cowles
Solution : The correct option is Henry Chandler Cowles.
Henry Chandler Cowles is a famous ecologist who studied plant life in the Indiana Dunes in 1896. His work in the Indiana Dunes is regarded as fundamental in the subject of ecology, and he is well-known
Question : Directions: In the following question, you have to identify the correct response from the given premises stated according to the following symbols. If ÷ stands for subtraction, – stands for addition, × stands for division, and + stands for multiplication, then which one of the following equations is correct?
Option 1: 35 ÷ 4 – 25 × 5 + 5 = 28
Option 2: 35 ÷ 4 – 25 × 5 + 5 = 61
Option 3: 35 ÷ 4 – 25 × 5 + 5 = 41
Option 4: 35 ÷ 4 – 25 × 5 + 5 = 56
Correct Answer: 35 ÷ 4 – 25 × 5 + 5 = 56
Solution : Given: ÷ stands for subtraction, – stands for addition, × stands for division, and + stands for multiplication.
Let's check the options – First option: 35 ÷ 4 – 25 × 5 + 5 =
Question : In which of the following Vedas was the Dasarajna war (the war of ten kings) mentioned?
Option 1: Yajurveda
Option 2: Samaveda
Option 3: Rigveda
Option 4: Atharvaveda
Correct Answer: Rigveda
Solution : The correct option is Rigveda.
The Dasarajna war, also known as the Battle of the Ten Kings, is mentioned in the Rigveda, one of the oldest and most important sacred texts of Hinduism. This historical battle is described in several hymns in the Rigveda, particularly
Question : If $(a+\frac{1}{a})^{2}=3$, then the value of $(a^{6}-\frac{1}{a^{6}})$ will be:
Option 2: 3
Option 3: 0
Solution : Given: $(a+\frac{1}{a})^{2}=3$ $\therefore (a+\frac{1}{a})=\sqrt3$ Cubing both sides, we get $a^3+\frac{1}{a^3}+3×a×\frac{1}{a}(a+\frac{1}{a})=3\sqrt3$ ⇒ $a^3+\frac{1}{a^3}+3(\sqrt3)=3\sqrt3$ ⇒ $a^3+\frac{1}{a^3}=3\sqrt3-3\sqrt3=0$ To find: $(a^{6}-\frac{1}{a^{6}})$ $(a^{6}-\frac{1}{a^{6}})=(a^{3}-\frac{1}{a^{3}})$$(a^{3}+\frac{1}{a^{3}})$ Putting the value of $a^3+\frac{1}{a^3}$, we get $(a^{6}-\frac{1}{a^{6}})=(a^{3}-\frac{1}{a^{3}})×0$ ⇒ $(a^{6}-\frac{1}{a^{6}})=0$ Hence, the correct answer is 0.
Question : Directions: A series is given with one term missing. Select the correct alternative from the given ones that will complete the series. NDRF, NZJT, NVBH, NRTV, ?
Option 1: NJRM
Option 2: NTQC
Option 3: NNLJ
Option 4: NIRQ
Correct Answer: NNLJ
Solution : Given: NDRF, NZJT, NVBH, NRTV, ?
The first letter of each term is the same. Subtract 4 and 8 from the place value of the second and third letters respectively, and add 14 to the place value of the fourth letter of the previous term
Question : The compound interest earned in two years at 15% per annum is Rs. 20,640. What is the sum invested (in Rs.)?
Option 1: 64000
Option 2: 60000
Option 3: 56000
Option 4: 52000
Correct Answer: 64000
Solution : Rate, R = 15% Term, n = 2 years Total amount = Rs. 20,640 Let the sum invested be $P$. Compound interest after 2 years = $P[(1+\frac{R}{100})^{2} –1)]$ ⇒ $20640$ = $P[(1+\frac{15}{100})^{2} –1)]$ ⇒ $20640$ = $P[(\frac{115}{100})^{2} –1)]$ ⇒ $20640$ = $P[(\frac{23}{20})^{2} –1)]$ ⇒ $20640$
Question : Select the most appropriate meaning of the given idiom. At cross purposes.
Option 1: Developing and amplifying ideas given.
Option 2: Finalising ideas and plans.
Option 3: Blindly following each other's ideas.
Option 4: Disagreeing with each other's ideas.
Correct Answer: Disagreeing with each other's ideas.
Solution : The correct choice is the fourth option.
The idiom at cross purposes describes a situation in which two or more people are working or talking about something, but their goals, intentions, or understanding of the situation are different or conflicting.
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