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Staff Selection Commission Combined Graduate Level Exam

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Question : Select the most appropriate collocating word to fill in the blank.

After having understood the ill effects, he said he would ________ drinking alcohol.

Option 1: quit

Option 2: finish

Option 3: close

Option 4: terminate

Team Careers360 20th Jan, 2024

Correct Answer: quit


Solution : The correct choice is the first option.

Quit is used with "drinking alcohol" to express the action of stopping or giving up the habit of consuming alcohol. It fits naturally with the context of the sentence, indicating that the person has decided to cease

9 Views

Question : Which of the following metals can deposit copper from copper sulphate solution?

Option 1: Platium

Option 2: Mercury

Option 3: Iron

Option 4: Gold

Team Careers360 15th Jan, 2024

Correct Answer: Iron


Solution : The correct option is Iron.

Through a displacement or redox process, iron (Fe) may deposit copper from a copper sulphate (CuSO4) solution. The following is a representation of the reaction:        CuSO4(aq) + Fe(s) -> FeSO4(aq) + Cu(s); Iron (Fe) displaces copper (Cu) from the

24 Views

Question : If $a=299, b=298, c=297$, then the value of $2a^3+2b^3+2c^3-6abc$ is:

Option 1: 5154

Option 2: 5267

Option 3: 5364

Option 4: 5456

Team Careers360 11th Jan, 2024

Correct Answer: 5364


Solution : Given: $a=299, b=298, c=297$
We know that the algebraic identity is $(a^3+b^3+c^3-3abc)=\frac{1}{2} \times(a+b+c)[(a-b)^2+(b-c)^2+(c-a)^2]$
$2a^3+2b^3+2c^3-6abc$
$=2(a^3+b^3+c^3-3abc)$
$=2\times\frac{1}{2} \times(a+b+c)[(a-b)^2+(b-c)^2+(c-a)^2]$
$=2\times\frac{1}{2} \times(299+298+297)[(299-298)^2+(298-297)^2+(297-299)^2]$
$=894[1^2+1^2+2^2]=894\times6$
$= 5364$
Hence, the correct answer is 5364.

22 Views

Question : Sunanda Nair is famous for performing which of the following dance forms?

Option 1: Kathak

Option 2: Odissi

Option 3: Yakshagana

Option 4: Mohiniyattam

Team Careers360 7th Jan, 2024

Correct Answer: Mohiniyattam


Solution : The correct answer is Mohiniyattam.

Sunanda Nair is a renowned Indian classical dancer known for performing the dance form Mohiniyattam. It is a traditional dance style from the southern Indian state of Kerala. It is characterised by its graceful and swift movements, expressive storytelling,

29 Views

Question : The denominator of a fraction is 4 more than twice the numerator. When the numerator is increased by 3 and the denominator is decreased by 3, the fraction becomes $\frac{2}{3}$. What is the difference between the denominator and numerator of the original fraction?

Option 1: 13

Option 2: 10

Option 3: 12

Option 4: 11

Team Careers360 24th Jan, 2024

Correct Answer: 11


Solution : Let the original fraction be $\frac{x}{y}$ 
According to the question,
$y = 2x + 4$ .............(1)
When 3 is added to the numerator and 3 is subtracted from the denominator the fraction becomes $\frac{2}{3}$
⇒ new fraction = $\frac{x + 3}{y – 3} = \frac{2}{3}$

9 Views

Question : Who among the following proposed the term ‘ecosystem’?

Option 1: A. G. Tansley

Option 2: Grinnell

Option 3: Lindeman

Option 4: Turesson

Team Careers360 25th Jan, 2024

Correct Answer: A. G. Tansley


Solution : The correct option is A. G. Tansley.

The term ecosystem was proposed by Sir Arthur Tansley, a British botanist and ecologist, in 1935. In addition to coining the term, Tansley made several significant contributions to ecology, including developing the concept of the

8 Views

Question : If for any acute angle A, $\sin A+\sin^{2} A=1$, then the value of $\cos^{2}A+\cos^{4}A$ is:

Option 1: –1

Option 2: 1

Option 3: 2

Option 4: 0

Team Careers360 10th Jan, 2024

Correct Answer: 1


Solution : Given: $\sin A+\sin^{2} A=1$ ----(1)
⇒ $\sin A=1–\sin^{2} A$
⇒ $\sin A=\cos^{2} A$ -----(2)
⇒ $\sin^{2} A=\cos^{4} A$ -----(3)
From equation (2) and (3), we get:
So, $\cos^{2} A+\cos^{4} A=\sin A+\sin^{2} A$
⇒ $\cos^{2} A+\cos^{4} A=1$
Hence, the correct answer is 1.

9 Views

Question : If $x^{2}+\frac{1}{x^{2}} = 98(x>0)$, then the value of $x^{3}+\frac{1}{x^{3}}$ is:

Option 1: 970

Option 2: 1030

Option 3: –970

Option 4: –1030

Team Careers360 22nd Jan, 2024

Correct Answer: 970


Solution : Given: $x^{2}+\frac{1}{x^{2}} = 98$
We know, $(x+y)^{2}= x^{2}+y^{2}+2xy$
⇒ $(x+\frac{1}{x})^{2}= x^{2}+\frac{1}{x^{2}}+2(x)(\frac{1}{x})$
⇒ $(x+\frac{1}{x})^{2}= 98+2$
⇒ $(x+\frac{1}{x})^{2}= 100$
⇒ $ (x+\frac{1}{x})= 10$
Now,
$x^{3}+\frac{1}{x^{3}} = (x+\frac{1}{x})^{3}-3(x)(\frac{1}{x})(x+\frac{1}{x})$
= $10^{3}-3(10)$
= $1000-30$
= $970$
Hence, the correct answer is 970.

15 Views

Question : If $\mathrm{p}=\frac{\sqrt{2}+1}{\sqrt{2}-1}$ and $\mathrm{q}=\frac{\sqrt{2}-1}{\sqrt{2}+1}$ then, find the value of $\frac{\mathrm{p}^2}{\mathrm{q}}+\frac{\mathrm{q}^2}{\mathrm{p}}$.

Option 1: 200

Option 2: 196

Option 3: 198

Option 4: 188

Team Careers360 8th Jan, 2024

Correct Answer: 198


Solution : Given:
$\mathrm{p}=\frac{\sqrt{2}+1}{\sqrt{2}-1}$, $\mathrm{q}=\frac{\sqrt{2}-1}{\sqrt{2}+1}$
Rationalising $p$, we get:
$p= 3+2\sqrt{2}$
⇒ $p^2=17+12\sqrt{2}$
$\mathrm{q}=\frac{\sqrt{2}-1}{\sqrt{2}+1}$
Rationalising $q$, we get:
$q= 3-2\sqrt{2}$
⇒ $q^2=17-12\sqrt{2}$
$\therefore$ $\frac{\mathrm{p}^2}{\mathrm{q}}+\frac{\mathrm{q}^2}{\mathrm{p}}=(\frac{17+12\sqrt{2}}{3-2\sqrt{2}})+(\frac{17-12\sqrt{2}}{3+2\sqrt{2}})$
⇒ $\frac{\mathrm{p}^2}{\mathrm{q}}+\frac{\mathrm{q}^2}{\mathrm{p}}=\frac{(17+12\sqrt{2})(3+2\sqrt{2})+(17-12\sqrt{2})(3-2\sqrt{2})}{(3+2\sqrt{2})(3-2\sqrt{2})}$
⇒ $\frac{\mathrm{p}^2}{\mathrm{q}}+\frac{\mathrm{q}^2}{\mathrm{p}}=\frac{2\times 17\times 3+2\times 12\times2\times 2}{(3+2\sqrt{2})(3-2\sqrt{2})}$
⇒ $\frac{\mathrm{p}^2}{\mathrm{q}}+\frac{\mathrm{q}^2}{\mathrm{p}}=198$
Hence, the correct answer is 198.

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