Staff Selection Commission Combined Graduate Level Exam
Question : The declaration that Democracy is a Government 'of the people, by the people; for the people' was made by
Option 1: George Washington
Option 2: Winston Churchill
Option 3: Abraham Lincoln
Option 4: Theodore Roosevelt
Correct Answer: Abraham Lincoln
Solution : The correct answer is Abraham Lincoln.
Abraham Lincoln made the claim that democracy is a government "of the people, by the people, and for the people" in his Gettysburg Address on November 19, 1863. He served as the sixteenth President of the United States.
Question : What is the value of $\text{cosec}15°\sec 15°?$
Option 1: 0.5
Option 2: 4
Option 3: 2
Option 4: 1
Correct Answer: 4
Solution : $\text{cosec}15°\sec 15°$ $=\frac{1}{\sin 15°}\frac{1}{\cos 15°}$ Multiplying and dividing by 2, we get ⇒ $\frac{2}{2\sin 15° \cos 15°}$ $= \frac{2}{\sin30°}$ $= \frac{2}{\frac{1}{2}}$ $= 2\times 2 = 4$ Hence, the correct answer is 4.
Question : What is humidity?
Option 1: When the water vapour transfers into water from the air.
Option 2: When water vapour is present in the air.
Option 3: When the other gases transfer to air.
Option 4: When air is present in the water.
Correct Answer: When water vapour is present in the air.
Solution : The correct option is When water vapour is present in the air.
The amount of water vapour present in the air is its humidity. It depends on temperature and pressure.
High humidity can make it feel hotter and
Question : Simplify: $\frac{256 x^4-16 y^4}{\left(80 x^2-20 y^2\right)\left(16 x^2+4 y^2\right)}$
Option 1: $5$
Option 2: $\frac{1}{20}$
Option 3: $\frac{1}{5}$
Option 4: $\frac{2}{5}$
Correct Answer: $\frac{1}{5}$
Solution : To simplify the given expression, let's factorize the numerator and the denominator first: Numerator $=256x^4-16y^4$ $=16(16x^4-y^4)$ $=16(4x^2+y^2)(4x^2-y^2)$ Denominator $=\left(80x^2-20y^2\right)\left(16x^2+4 y^2\right)$ $=20(4x^2-y^2)×4(4x^2+y^2)$ $=80(4x^2+y^2)(4x^2–y^2)$ So, now $\frac{256x^4–16y^4}{\left(80x^2–20y^2\right)\left(16x^2+4 y^2\right)}$ $=\frac{16(4x^2+y^2)(4x^2-y^2)}{80(4x^2+y^2)(4x^2–y^2)}$ $=\frac{1}{5}$ Hence, the correct answer is $\frac{1}{5}$.
Question : Directions: Which of the following letter clusters will replace the question mark (?) in the given series? HFK, KHM, ?, QLQ, TNS
Option 1: NJO
Option 2: OKN
Option 3: MJN
Option 4: MKP
Correct Answer: NJO
Solution : Given: HFK, KHM, ?, QLQ, TNS
In the given series, add 3, 2, and 2 to the place value of the first, second, and third letters of the previous term respectively to form the next term. HFK→H + 3 = K; F + 2 =
Question : An article costs Rs.4,000 to a shopkeeper, who marks its price at Rs.8,400. The shopkeeper sells it to a customer at a discount of 25%. The customer gets a further discount of 15% on the discounted price if the customer redeems a coupon issued by the store previously. What is the profit percentage (to the nearest integer) earned by the shopkeeper in this transaction?
Option 1: 34%
Option 2: 51%
Option 3: 42%
Option 4: 36%
Correct Answer: 34%
Solution : Given, The cost for a shopkeeper = Rs. 4,000 Marked Price = Rs. 8,400 Discount A = 25%. Discount B = 15% ⇒ Final discount percentage $= 25 + 15 - \frac{25 \times 15}{100} = 36.25$% And, Selling price of the article = $8400 \times
Question : In a $\triangle ABC$, if $\angle A=90^{\circ}, AC=5 \mathrm{~cm}, BC=9 \mathrm{~cm}$ and in $\triangle PQR, \angle P=90^{\circ}, PR=3 \mathrm{~cm}, QR=8$ $\mathrm{cm}$, then:
Option 1: $\triangle ABC \cong \triangle PQR$
Option 2: $ar(\triangle ABC)\neq ar(\triangle PQR)$
Option 3: $ar(\triangle ABC) \leq ar(\triangle PQR)$
Option 4: $ar(\triangle ABC)=ar(\triangle PQR)$
Correct Answer: $ar(\triangle ABC)\neq ar(\triangle PQR)$
Solution : Given: In a $\triangle ABC$, if $\angle A=90^{\circ}, AC=5 \mathrm{~cm}, BC=9 \mathrm{~cm}$ and in $\triangle PQR, \angle P=90^{\circ}, PR=3 \mathrm{~cm}, QR=8$ $\mathrm{cm}$ Since the sides are not equal, $\triangle ABC \cong \triangle PQR$ is wrong. In $\triangle ABC$, $AB=\sqrt{9^2-5^2}=\sqrt{56} =2\sqrt{14}$ Area of
Question : A person lent a certain sum of money at the annual rate of 25 percent on simple interest. In 6 years the interest amounted to Rs. 360 more than the sum lent. What is the sum lent?
Option 1: Rs. 600
Option 2: Rs. 360
Option 3: Rs. 720
Option 4: Rs. 540
Correct Answer: Rs. 720
Solution : Let the sum be Rs. $x$. Simple interest = $x+360$ We know that, Simple interest = $\frac{\text{Principal × rate × time}}{100}$ ⇒ $x+360 = \frac{x \times 25 \times 6}{100}$ ⇒ $2x+720 = 3x$ $\therefore x=720$ Hence, the correct answer is Rs. 720.
Question : Directions: In the following question, select the missing number from the given series. 7, 21, 63,189, 567, ?
Option 1: 1701
Option 2: 1800
Option 3: 1720
Option 4: 1781
Correct Answer: 1701
Solution : Given: 7, 21, 63,189, 567, ?
Multiply each number by 3 to get the next term in the series – 7 × 3 = 21; 21 × 3 = 63; 63 × 3 = 189; 189 × 3 = 567; 567 × 3 = 1701
Question : When is the International Day of the Girl Child celebrated?
Option 1: 14 October
Option 2: 12 October
Option 3: 13 October
Option 4: 11 October
Correct Answer: 11 October
Solution : The correct answer is 11 October.
The International Day of the Girl Child occurs annually on October 11. This date is celebrated worldwide, with a focus on advocating for girls' rights and equality and addressing their unique challenges. The day emphasises the global
The Question containing Inaapropriate or Abusive Words
Question lacks the basic details making it difficult to answer
Topic Tagged to the Question are not relevant to Question
Question drives traffic to external sites for promotional or commercial purposes
The Question is not relevant to User
And never miss an important update
