Staff Selection Commission Combined Graduate Level Exam
Question : The radius of a circle is 5 cm. The length of chord AB in this circle is 6 cm. What is the distance of this chord from the centre of the circle?
Option 1: 4 cm
Option 2: 5 cm
Option 3: 6 cm
Option 4: 8 cm
Correct Answer: 4 cm
Solution : Let $OB$ be the radius of the circle and $OD$ be the distance from the centre to the chord $AB$. The radius of a circle, $OB$ = 5 cm Length of chord $AB$ = 6 cm Now, we know altitude from the centre of
Question : Mahatma Gandhi returned to India from _____ in January 1915.
Option 1: South Africa
Option 2: England
Option 3: U.S.A
Option 4: Russia
Correct Answer: South Africa
Solution : The correct answer is South Africa.
In January 1915, Gandhi Ji returned to India from South Africa. They were encouraged to free themselves from decades of slavery by Mahatma Gandhi, who also taught them the value of freedom and gave them Satyagrah, the greatest
Question : Comprehension: In the following passage, some words have been deleted. Read the passage carefully and select the most appropriate option to fill in each blank. Comics have (1) ________ many superheroes. Bantul, the great, was (2) ________ in the year 1965, in the backdrop of the Indo-Pak war. Indrajal comics was set up in 1964, and (3) __________ Aabid Surti, who gave birth to a character called Bhadur in 1976, wearing kurta and jeans. Raj comics too (4) ________ into this sphere with their (5) ________ toons Nagraj, Tiranga, and Shakti together called Brahman Rakshak (protectors of the universe). Select the most appropriate option to fill in the blank number 5.
Option 1: noted
Option 2: influential
Option 3: famous
Option 4: good
Correct Answer: famous
Solution : The correct choice is the third option.
Explanation: The passage discusses various comic book superheroes introduced by different publishers. The context implies that the superheroes introduced by Raj comics—Nagraj, Tiranga, and Shakti—are being referred to. The word famous fits well here, as it suggests
Question : The difference between Compound Interest and Simple Interest on a certain sum of money for 2 years at 5% per annum is Rs. 41. What is the total sum?
Option 1: Rs. 7,200
Option 2: Rs. 9,600
Option 3: Rs. 16,400
Option 4: Rs. 8,400
Correct Answer: Rs. 16,400
Solution : The difference between the Simple Interest and Compound Interest on a certain sum of money $P$ for 2 years at $R$% per annum is given by: $(CI - SI) = \frac{PR^{2}}{100^{2}}$ According to Question, The difference between CI and SI for 2 years is
Question : Directions: If a mirror is placed on line AB, which of the answer figures is the right image of the given figure?
Option 1:
Option 2:
Option 3:
Option 4:
Correct Answer:
Solution : As per mirror image properties, closer things appear closer to the mirror in reflection. According to the information provided, if the mirror is placed on the right side of the figure (on line AB), the right of the reflected image will appear as the
Question : Study the given bar graph carefully and answer the following question. What is the difference between the average demand and the average production of the three companies taken together?
Option 1: 1,275
Option 2: 1,530
Option 3: 1,850
Option 4: 1,456
Correct Answer: 1,456
Solution : The demand of P, Q, and R companies is $(3800 + 4532 + 5318) = 13650$ Production of P, Q, and R companies is $(3620 + 2829 + 2833) = 9282$ Average = $\frac{\text{Sum of all the observations}}{{\text{Total number of observations}}}$ The average demand of
Question : If $\frac{a^2+b^2}{c^2}=\frac{b^2+c^2}{a^2}=\frac{c^2+a^2}{b^2}=\frac{1}{k}$, $(k\neq 0)$, then $k$=?
Option 1: $2$
Option 2: $1$
Option 3: $0$
Option 4: $\frac{1}{2}$
Correct Answer: $\frac{1}{2}$
Solution : Given: $\frac{a^2+b^2}{c^2}=\frac{b^2+c^2}{a^2}=\frac{c^2+a^2}{b^2}=\frac{1}{k}$ Solving the expressions, we get: $k(a^2+b^2)=c^2$ (equation 1). $k(b^2+c^2)=a^2$ (equation 2). $k(c^2+a^2)=b^2$ (equation 3). On adding all the equations, we get– $(a^2+b^2+c^2)=k(a^2+b^2+b^2+c^2+c^2+a^2)$ ⇒ $(a^2+b^2+c^2)=2k(a^2+b^2+c^2)$ ⇒ $k=\frac{1}{2}$ Hence, the correct answer is $\frac{1}{2}$.
Question : The minute hand of a clock is 20 cm long. Find the area on the face of the clock swept by the minute hand between 8 a.m. and 8:45 a.m.
Option 1: $\frac{6600}{7}$ cm2
Option 2: $\frac{6600}{9}$ cm2
Option 3: $\frac{6600}{18}$ cm2
Option 4: $\frac{6600}{14}$ cm2
Correct Answer: $\frac{6600}{7}$ cm2
Solution : Length of minute hand = 20 cm As we know the 1 minute angle made by the minute hand is $6^\circ$ In 45 minutes, the minute hand will make = $45(6^\circ)= 270^\circ$ Area swept by minute hand in 45 minutes = $\frac{\theta}{360^{\circ}}\times \pi
Question : Two posts are $x$ metres apart and the height of one is double that of the other. If, from the midpoint of the line joining their feet, an observer finds the angular elevation of their tops to be complementary, then the height (in metres) of the shorter posts is:
Option 1: $\frac{x}{2\sqrt{2}}$
Option 2: $\frac{x}{4}$
Option 3: $x\sqrt{2}$
Option 4: $\frac{x}{\sqrt{2}}$
Correct Answer: $\frac{x}{2\sqrt{2}}$
Solution : Let BD be the distance between two posts is $x$ metres. $\therefore$ OB = OD = $\frac{x}{2}$ From $\triangle$OCD $\tan\theta$ = $\frac{CD}{OD}$ $\tan\theta$ = $\frac{h}{\frac{x}{2}}$= ${\frac{2h}{x}}$............(equation 1) From $\triangle$OAB $\tan(90–\theta)=\frac{AB}{OB}$ $\cot\theta$ = $\frac{2h}{\frac{x}{2}}$= ${\frac{4h}{x}}$............(equation 2) Multiplying both equations, we get: $\tan\theta×\cot\theta$ = ${\frac{2h}{x}}×{\frac{4h}{x}}$ ⇒ 1
Question : The average weight of three men is increased by 4 kg when one of them, whose weight is 100 kg, is replaced by another man. What is the weight of the new man?
Option 1: 107 kg
Option 2: 103 kg
Option 3: 104 kg
Option 4: 112 kg
Correct Answer: 112 kg
Solution : Given: The average weight of three men is increased by 4 kg. One of them, whose weight is 100 kg, is replaced by another man. According to the question, ⇒ Weight of new man = increase weight $×$ number of persons + weight of
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