Staff Selection Commission Combined Graduate Level Exam
Question : Directions: In the following question, some parts of the sentence may have some errors. Find out which part of the sentence has an error and select the appropriate option. If the sentence is free from error, select "No error".
His parents usually spent (1) / their summer in Ooty (2) / but this year they are spending it in Darjeeling. (3) / No error (4)
Option 1: (1)
Option 2: (2)
Option 3: (3)
Option 4: (4)
Correct Answer: (1)
Solution : The error lies in the first part of the sentence.
The verb spend should be used in the present form to talk about habitual or regular actions. So spent (past tense) is incorrect in this context.
Therefore, the correct sentence is: "His parents usually spend
Question : Most of the Chlorophyceae have one or more storage bodies called ______ located in the chloroplasts.
Option 1: stomata
Option 2: carotenoids
Option 3: pyrenoids
Option 4: chlorophyll
Correct Answer: pyrenoids
Solution : The correct answer is pyrenoids.
The majority of chlorophytes have one or more pyrenoids, which are starch-sheathed central proteinaceous bodies that are located all around the chloroplast. A protein-rich body called a pyrenoid is present in green algae, or Chlorophyceae members. They are exclusive
Question : The length of a side of an equilateral triangle is 8 cm. The area of the region lying between the circumcircle and the incircle of the triangle is __________ ( Use: $\pi = \frac{22}{7}$)
Option 1: $50\frac{1}{7}\ \text{cm}^2$
Option 2: $50\frac{2}{7}\ \text{cm}^2$
Option 3: $75\frac{1}{7}\ \text{cm}^2$
Option 4: $75\frac{2}{7}\ \text{cm}^2$
Correct Answer: $50\frac{2}{7}\ \text{cm}^2$
Solution : Given: Side of the equilateral triangle, $a$ = 8 cm Radius of incircle = $\frac{a}{2\sqrt{3}}$ cm Radius of circumcircle = $\frac{a}{\sqrt{3}}$ cm So, the required area = Area of circumcircle – Area of incircle = $\pi (\frac{a}{\sqrt{3}})^2-\pi (\frac{a}{2\sqrt{3}})^2$ = $\pi (\frac{8}{\sqrt{3}})^2-\pi (\frac{8}{2\sqrt{3}})^2$ = $64\pi(\frac{1}{3}-\frac{1}{12})$
Question : Directions: Select the odd group of numbers. (NOTE: Operations should be performed on the whole numbers, without breaking down the numbers into their constituent digits. E.g.13 – operations on 13 such as adding/subtracting/multiplying etc. to 13 can be performed. Breaking down 13 into 1 and 3 and then performing mathematical operations on 1 and 3 is not allowed)
Option 1: (137 – 142 – 147 )
Option 2: (117 – 122 – 129 )
Option 3: (103 – 108 – 113 )
Option 4: (131 – 136 – 141 )
Correct Answer: (117 – 122 – 129 )
Solution : Let's check the options – First option: (137 – 142 – 147 ); 137 + 5 = 142; 142 + 5 = 147 Second option: (117 – 122 – 129 ); 117 + 5 = 122; 122 + 7 =
Question : Direction: Select the missing number from the given alternatives.
Option 1: 11
Option 2: 6
Option 3: 3
Option 4: 2
Correct Answer: 3
Solution : Given:
In the first column, 6 ÷ 3 x 4 = 8
In the second column, 18 ÷ 2 x 3 = 27
In the third column, 15 ÷ 5 x ? =
Question : Comprehension:
In the following passage, some words have been deleted. Read the passage carefully and select the most appropriate option to fill in each blank.
Swaminathan had a table on which all his things, his coat, cap, slate, ink bottle, and books, were thrown in a confused (1)______ He sat on his stool and shut his eyes to (2) ________ what work he had for the day: first of course there was arithmetic – those five (3)_______ in profit and loss; then there was English – he had to copy down a page from his English lesson and write dictionary meanings of (4) _______ words; and then there was geography. And only two hours before him to do all this heap of work and get (5) ______ for school.
Question:
Select the most appropriate option to fill in the blank number 4.
Option 1: rigid
Option 2: awkward
Option 3: difficult
Option 4: visible
Correct Answer: difficult
Solution : The correct choice is the third option.
In the context of the passage, the word difficult is suitable to describe the task related to English. The term difficult aligns with the challenge or complexity associated with understanding and defining certain words.
The meanings of
Question : If $\operatorname{cosec} \theta+\cot \theta=p$, then the value of $\frac{p^2-1}{p^2+1}$ is:
Option 1: $\cos \theta$
Option 2: $\sin \theta$
Option 3: $\cot \theta$
Option 4: $\operatorname{cosec} \theta$
Correct Answer: $\cos \theta$
Solution : Given, $\operatorname{cosec} \theta+\cot \theta=p$ Squaring both sides, we get, $\operatorname{cosec}^2 \theta+\cot^2 \theta+2\operatorname{cosec} \theta\cot \theta=p^2$ ----------------------(1) Adding 1 on both sides of equation (1), $\operatorname{cosec}^2 \theta+(\cot^2 \theta+1)+2\operatorname{cosec} \theta\cot \theta=p^2+1$ $⇒2\operatorname{cosec}^2 \theta+2\operatorname{cosec} \theta\cot \theta=p^2+1$ ---------------------------(2) Subtracting 1 from both sides of equation (1), $(\operatorname{cosec}^2-1) \theta+\cot^2 \theta+2\operatorname{cosec}
Question : Select the option that expresses the given sentence in active voice.
Elaborate plans are being made for Aarushi’s destination wedding.
Option 1: They are making elaborate plans for Aarushi’s destination wedding.
Option 2: They have made elaborate plans for Aarushi’s destination wedding.
Option 3: They have been making elaborate plans for Aarushi’s destination wedding.
Option 4: They made elaborate plans for Aarushi’s destination wedding.
Correct Answer: They are making elaborate plans for Aarushi’s destination wedding.
Solution : The correct choice is the first option.
Active voice is the voice in which the subject performs the action.
The structure of the sentence in the active voice in the case of the present continuous tense is:
Question : If 3x + 4y – 2z + 9 = 17, 7x + 2y + 11z + 8 = 23, and 5x + 9y + 6z – 4 = 18, then what is the value of x + y + z – 34?
Option 1: –28
Option 2: –14
Option 3: –31
Option 4: –45
Correct Answer: –31
Solution : Given: 3x + 4y – 2z + 9 = 17 .......(i) 7x + 2y + 11z + 8 = 23 .......(ii) 5x + 9y + 6z – 4 = 18 ..........(iii) By adding equation (i), (ii), and (iii), we get, 15x + 15y + 15z
Question : A piece of wire 132 cm long is bent successively in the shapes of an equilateral triangle, a square, and a circle. The area will be largest in the shape of:
Option 1: Circle
Option 2: Equilateral triangle
Option 3: Square
Option 4: Equal in all the shapes
Correct Answer: Circle
Solution : The length of the wire is the same in all three cases, so it becomes the perimeter of each shape. (1). For an equilateral triangle with side length $a$, the perimeter = $3a$ $a = \frac{132}{3} = 44$ cm The area of an equilateral triangle
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