Correct Answer: GVJV

Solution : Given:
AJRX, CNXF, ERDN, ?, IZPD

In the above-given series, add 2, 4, 6 and 8 to the place value of the first, second, third and fourth letters of the given terms.
AJRX→A + 2 = C; J + 4 = N; R + 6

Correct Answer: 4

Solution : According to the question,
$2\pi rh \times 2= \pi r^2h$
⇒ $4 = r$
⇒ $r = 4\ \mathrm{units}$
Hence, the correct answer is 4.

Correct Answer: 14%

Solution : Given:
Savings of the man = $33\tfrac{1}{3}\% = \frac{1}{3}$rd of income
Let the original income be $300x$
⇒ Original Savings = $100x$
So, Original Expenditure $=300x-100x = 200x$
According to the question,
New savings $=100x \times \frac{122}{100} = 122x$
New expenditure $=200x \times \frac{110}{100} =

Correct Answer: 35, 3

Solution : Given:
I. 6 – 5 × 9 + 8 ÷ 2
II. 6 – 4 + 9 × 5 ÷ 3

Let's solve each equation after interchanging signs and numbers according to the instructions.
On interchanging the signs and numbers in the first equation,

Correct Answer: Muhammad bin Tughluq

Solution : The correct answer is Muhammad bin Tughluq.

The Tughlaq Sultan who issued copper coins instead of silver ones was Muhammad bin Tughluq. During his reign, he introduced copper coins known as "tankas" to replace the silver coins. This decision, among other factors,

Correct Answer: 420

Solution : Given: A group of men decided to do a job in 11 days but 16 men left the work after each day.
Total time taken to complete the work = 15 days
Let there be $x$ number of men in the group with efficiency of

Correct Answer: $\frac{m^{2}-1}{m^{2}+1}$

Solution : Given: $\sec\theta+\tan\theta=m$
⇒ $1+\sin\theta=m\cos\theta$
Squaring both sides,
$1+2\sin\theta+\sin^{2}\theta=m^{2}\cos^{2}\theta$
⇒ $1+2\sin\theta+\sin^{2}\theta=m^{2}(1-\sin^{2}\theta)$
⇒ $(1+m^{2})\sin^{2}\theta+2\sin\theta+(1-m^{2})=0$
⇒ $\sin\theta = \frac{-2\pm\sqrt{2^2-4(1+m^2)(1-m^2)}}{2(1+m^{2})}$
⇒ $\sin\theta =\frac{-2\pm 2m^2}{2(1+m^{2})}$
⇒ $\sin\theta =\frac{m^2-1^2}{(1+m^{2})}$ and $\sin\theta =-1$
⇒ $\sin\theta=\frac{m^{2}-1}{m^{2}+1},-1$
Hence, the correct answer is $\frac{m^{2}-1}{m^{2}+1}$.

Correct Answer: 0.27

Solution : $x=\sqrt{1+\frac{\sqrt{3}}{2}}-\sqrt{1-\frac{\sqrt{3}}{2}}$
Squaring both sides, we get,
$⇒x^2=1+\frac{\sqrt{3}}{2}+1-\frac{\sqrt{3}}{2}-2(\sqrt{1-\frac{3}{4}})$
$⇒x^2=1$
$x=1$ or $x=-1$
Taking $x=1$, we get,
$⇒\frac{\sqrt{3}-x}{\sqrt{3}+x}$
$=\frac{\sqrt{3}-1}{\sqrt{3}+1}$
$=\frac{\sqrt{3}-1}{\sqrt{3}+1}\times\frac{\sqrt{3}-1}{\sqrt{3}+1}$
$=\frac{(\sqrt{3}-1)^2}{3-1}$
$=2-\sqrt{3}$
$=2-1.73$ [As the value of $\sqrt3=1.73$]
$=0.27$
Hence, the correct answer is 0.27.

Correct Answer: Rs. 90

Solution : Let the price of the third variety be Rs. $x$ per kg.
The ratio of varieties of rice in the mixture is $1 : 2 : 3$.
Let the amount of the first, second, and third varieties of rice in the mixture be 1

Correct Answer: high

Solution : The correct choice is the second option.

The word chances is often collocated with "high" to convey a likelihood or probability of success. In this context, the phrase "high chances" indicates a favourable or significant probability of winning the match.

The meanings of the